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OLEGan [10]
3 years ago
9

Find the value of tan θ for the angle shown. A line is drawn from the origin through the point square root of thirty-three comma

negative four. The angle theta is given as the measurement from the positive x axis counterclockwise to the line.

Mathematics
2 answers:
Bogdan [553]3 years ago
8 0
If you draw this triangle on a graph as described, tan theta is -4(square root)33/33

GaryK [48]3 years ago
4 0
<h2>Answer:</h2>

The value of tan θ is:

             \tan \theta=-\dfrac{4}{\sqrt{33}}

<h2>Step-by-step explanation:</h2>

From the given right angled triangle we have:

          Base of the triangle i.e. OA is: √33 units

and Perpendicular length of triangle  i.e. AB is: 4 units

Hence, in the given right angled triangle we will use the trignometric ratio corresponding to the angle (360°-θ) as:

\tan (360-\theta)=\dfrac{perpendicular}{base}\\\\\\\tan (360-\theta)=\dfrac{4}{\sqrt{33}}

As we know that:

\tan (360-\theta)=-\tan \theta

Hence,

-\tan \theta=\dfrac{4}{\sqrt{33}}\\\\\\i.e.\\\\\\\tan \theta=-\dfrac{4}{\sqrt{33}}

                     Hence, the answer is:

               \tan \theta=-\dfrac{4}{\sqrt{33}}

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Could someone explain and help
vichka [17]

Answer:

  80°

Step-by-step explanation:

The sum of the two angles (red and blue) is 145°, so you have ...

  (4x +5)° +(6x -10)° = 145°

  10x = 150 . . . . . . . . divide by °, add 5, simplify

  x = 15 . . . . . . . . . . . divide by 10

Then the measure of the angle of interest is ...

  m∠XMN = (6x -10)° = (6·15 -10)° = 80°

8 0
3 years ago
If x = 7, what is the value of the expression above?
givi [52]

if x= 7 what is the value of x-4

7 - 4

=3

if y=3 what is the value of 8y

8 x 3

= 24

if x=7 what is the value of 3x-4

(3 x 7) - 4

= 17

if x=7 and y=3 what is the value of 2x-7y

(2 x 7) -(7 x 3)

= - 7

if x=7 and y=3 what is the value of 4y-X

(4 x 7) - 3

= 25

Hope this helps

8 0
3 years ago
Zero cannot be classified as which type of number ?
Sav [38]
Natural number
that is 1,2,3,4,5,6...

7 0
3 years ago
Read 2 more answers
Find a vector of magnitude 3 in the direction of v = 10i - 24k. The vector is Oi-Oj+k (Simplify your answer. Use integers or fra
Soloha48 [4]

Given :

A vector v = 10i - 24k.

To Find :

A vector of magnitude 3 in the direction of v = 10i - 24k.

Solution :

Unit vector in the direction  of vector v is :

\^{v}=\dfrac{v}{|v|}\\\\\^{v}=\dfrac{10i-24k}{\sqrt{10^2+24^2}}\\\\\^{v}=\dfrac{10i-24k}{26}

Now , vector of magnitude 3 in direction v is :

r=3 \^{v}\\\\r=3\times \dfrac{ (10i-24k)}{26}\\\\r=\dfrac{3}{13} (5i-12k)

Hence , this is the required solution .

6 0
3 years ago
Karen, Trey, and Dante have a total of 75 in their wallets. Karen has 5 more than Trey. Dante has 2 times what Karen has. How mu
Taya2010 [7]

Answer: Karen has 20, Trey has 15, Dante has 40

Step-by-step explanation:

Karen=x+5    Trey=x     Dante=2x+10

            x+x+5+2x+10=75

                 4x+15=75

                   4x=60

                     x=15

5 0
2 years ago
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