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marin [14]
3 years ago
12

A 25.0-cm long cylindrical glass tube, sealed at one end, is filled with ethanol. The mass of ethanol needed to fill the tube is

found to be 45.23 g. The density of ethanol is 0.789 g/mL. Calculate the inner diameter of the tube in centimeters.
Chemistry
1 answer:
Inessa05 [86]3 years ago
6 0

Answer:

Therefore, internal diameter of the glass tube = 1.708 cm

Explanation:

Volume of ethanol = volume of glass tube

volume of ethanol = mass of ethanol/ density of ethanol

volume of ethanol = 45.23 g/ 0.789g/ml

volume of ethanol = 57.326 ml

Therefore volume of glass tube = 57.326 ml

1 ml = 1 cm³

Volume of glass tube in cm³ = 57.326 cm³

Volume of a cylinder = πd²h/4

where h = height of cylinder; d = internal diameter of cylinder

d = √(volume * 4/πh)

d = √(4 * 57.326 cm³ / 3.142 * 25)

d = 1.708 cm

Therefore, internal diameter of the glass tube = 1.708 cm

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The reaction P4 + 5O2 → P4O10 + 712 kcal is exothermic. True False
Nitella [24]

Answer: The correct answer is true.

Explanation:

There are two types of reactions based on the heat absorbed or released:

1. Exothermic reactions: In these reactions, heat is released. The energy of the products is less than the energy of the reactants. The \Delta H for these reactions is negative.

2. Endothermic reactions: In these reactions, heat is absorbed by the reactants. The energy of the products is more than the energy of the reactants. The \Delta H for these reactions is positive.

In the given equation:

P_4+5O_2\rightarrow P_4O_{10}+712kCal

The energy is written on the product side, which means that the heat is released in the reaction. Hence, the given equation is a exothermic reaction.

Therefore, the given statement is true.

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3 years ago
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Lab: Limiting Reactant and Percent Yield
natali 33 [55]

Answer:

pre lab information would be the thing you to ressearch the lab to get the information

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A potassium bromide solution is 8.34% potassium bromide by mass and its density is 1.03 g/ml. what mass of potassium bromide is
jenyasd209 [6]

Answer:-  3.84 grams

Solution:-  Volume of the sample is 44.8 mL and the density is 1.03 gram per mL.

From the density and volume we calculate the mass as:

mass = volume*density

44.8mL(\frac{1.03g}{mL})

= 46.1 g

From given info, potassium bromide solution is 8.34% potassium bromide by mass. It means if we have 100 grams of the solution then 8.34 grams of potassium bromide is present in. We need to calculate how many grams of potassium bromide are present in 46.1 grams of the solution.

The calculations could easily be done using dimensional analysis as:

46.1gSolution(\frac{8.34gKBr}{100gSolution})

= 3.84 g KBr

Hence, 3.84 grams of KBr are present in 44.8 mL of the solution.

8 0
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Why is the wavelength of 633 nm used to analyze the standard solutions and drink samples?
DanielleElmas [232]

Answer:

The correct option is;

A. Corresponding with orange light, is the wavelength that blue solutions absorb the most

Explanation:

The wavelength of 633 nm is the wavelength of red light emitted by the helium-neon laser also known as the He-Ne laser

According to absorption spectroscopy and the color wheel, a solution or drink sample that is efficient at absorbing light having a wavelength of 633 nm will appear blue, because, light at 633 nm is red and very close to orange which is the complementary color blue light.

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Equation balancing a. S(s) + O2(g) → SO3(8) b. 2Al(s) + 3C12(8) ► 2AICI,(s) E. 2NaOH(s) + H2SO,(ac) —Na,SO (ac) + H2O(1) d. CHg(
Debora [2.8K]

Answer:

a. S(s) + 3/2 O₂(g) → SO₃(g)

b. Al(s) + 3/2 Cl₂(g) → AICI₃(s)

c. 2 NaOH(s) + H₂SO₄(ac) → Na₂SO₄(ac) + 2 H₂O(l)

d. C₃H₈(g) + 5 O₂(g) → 3 CO₂(g) +  4 H₂O(g)

Explanation:

We will balance the equation using the trial and error method.

a. S(s) + O₂(g) → SO₃(g)

1. We will balance O atoms by multiplying O₂by 3/2.

S(s) + 3/2 O₂(g) → SO₃(g)

b. Al(s) + Cl₂(g) → AICI₃(s)

1. We will balance Cl atoms by multiplying Cl₂ by 3/2.

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c. NaOH(s) + H₂SO₄(ac) → Na₂SO₄(ac) + H₂O(l)

1. We will balance Na atoms by multiplying NaOH by 2.

2. We will balance H and O atoms by multiplying H₂O by 2.

2 NaOH(s) + H₂SO₄(ac) → Na₂SO₄(ac) + 2 H₂O(l)

d. C₃H₈(g) + O₂(g) → CO₂(g) +  H₂O(g)

1. We will balance C atoms by multiplying CO₂ by 3.

2. We will balance H atoms by multiplying H₂O by 4.

3. We will balance O atoms by multiplying O₂ by 5.

C₃H₈(g) + 5 O₂(g) → 3 CO₂(g) +  4 H₂O(g)

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