Based on this, Individual electrons in graphene have almost no mass compared to the other particles.
The material graphene consists of a single layer of carbon atoms arranged in a hexagonal lattice.
Electrons flowing through graphene can be scattered from impurities (such as foreign atoms in the lattice), from other electrons and from lattice vibrations known as phonons.
What happens to the electrons in graphene?
According to the researchers, such high values are a result of the photo thermoelectric effect. “It turns out that when you shine a light on graphene, the electrons in the material heat up, and remain hot, while the underlying carbon lattice remains cool,”
Why are electrons massless in graphene?
Yes, low energy electrons and holes in graphene can be thought of as massless because of the linear dispersion of the band structure near the K points.
This is an analogy to the relativistic energy dispersion E2=P2C2+M2C4, which becomes linear in momentum for m=0.
To learn more about electrons here
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Hi,
The atomic number of an element depends on how many protons there are in one atom of that element. If the atom has 3 protons, its atomic number will be 3.
Hope this helps! If my answer was not clear enough or you’d like further explanation please let me know.
Answer:
118.6nm
Explanation:
It is possible to calculate wavelength of any energetic process (As an ionization) using:
E = hc / λ <em>(1)</em>
<em>Where E is Energy, h is Planck constant (6.626x10⁻³⁴Js), c speed of light (3x10⁸ms⁻¹) and λ is wavelength In meters.</em>
As the energy to ionize 1 mole of iodine is 1009kJ, one atom requires:
(1009kJ / mol) ₓ (1mol / 6.022x10²³ atoms) = <em>1.6755x10⁻²¹kJ / atom</em>. = 1.6755x10⁻¹⁸J
Replacing in (1):
λ = hc / E
λ = 6.626x10⁻³⁴Js*3x10⁸ms⁻¹ / 1.6755x10⁻¹⁸J
λ = 1.186x10⁻⁷m
As 1m = 1x10⁹nm:
1.186x10⁻⁷m ₓ (1x10⁹nm / 1m) =
<h3>118.6nm</h3>
Answer:
[Cl⁻] = 0.135 M
Explanation:
The concentration of Cl⁻ is equal to the total moles of Cl⁻ divided by the total volume:
C = n/V
All of the moles of Cl⁻ come from dissociation of the KCl:
KCl ⇒ K⁺ + Cl⁻
We will calculate the moles of Cl⁻ based on the amount of KCl added by using the molar ratio of 1:1.
(0.345 mol/L)(63.0 mL) = (21.735 mmol KCl)(Cl⁻/KCl) = 21.735 mmol Cl⁻
Extra significant figure are kept to avoid round-off errors.
Now we can calculate the total volume, which is the sum of the volume of the three solutions added:
(39.0 mL) + (59.0 mL) + (63.0 mL) = 161.0 mL
Finally, we calculate the concentration of Cl⁻
[Cl⁻] = (21.735 mmol) / (161.0 mL) = 0.135 M
Answer:
The mixing of two chemicals may result in the production of a gas which is lost to the air. This will reduce the mass of the chemical mixture, because mass is being lost in a gaseous form.