As we know,
pH + pOH = 14
Or,
pOH = 14 - pH
Putting Value of pH,
pOH = 14 - 10.62
pOH = 3.38
pOH is converted into [OH⁻] as follow,
[OH⁻] = 10⁻pOH ∴ -pOH is in power, 10 means antilog
press shift and click log button
[OH⁻] = 10⁻³°³⁸
[OH⁻] = 0.0004168
[OH⁻] = 4.16 × 10⁻⁴
The ionization energy<span> for </span>hydrogen<span> is 1312 kilojoules per mole. This is the same ... Electrically neutral </span>atoms<span> include a </span>single<span> proton and electron held together.</span>
Answer:
Uranium mines operate in many countries, but more than 85% of uranium is produced in six countries: Kazakhstan, Canada, Australia, Namibia, Niger, and Russia. Historically, conventional mines open pit or underground were the main source of uranium.
Explanation:
Hope this helps
Answer:
Eat food
Explanation:
Food contain protein, carbohydrates, fats etc. These nutrients undergoes metabolic process and produced energy in cellular respiration.
There are two types of respiration:
1. Aerobic respiration
2. Anaerobic respiration
Aerobic respiration
It is the breakdown of glucose molecule in the presence of oxygen to yield large amount of energy. Water and carbon dioxide are also produced as a byproduct.
Glucose + oxygen → carbon dioxide + water + 38ATP
Anaerobic Respiration
It is the breakdown of glucose molecule in the absence of oxygen and produce small amount of energy. Alcohol or lactic acid and carbon dioxide are also produced as byproducts.
Glucose→ lactic acid/alcohol + 2ATP + carbon dioxide
This process use respiratory electron transport chain as electron acceptor instead of oxygen. It is mostly occur in prokaryotes. Its main advantage is that it produce energy (ATP) very quickly as compared to aerobic respiration.
Answer:
Cu(s) in Cu(NO₃)₂(aq)
Explanation:
The standard reduction potential (E°) is the energy necessary to reduce the atom in a redox reaction. When an atom reduces it gains electrons from other than oxides. As higher is E°, easily it will reduce. The substance that reduces is at the cathode of a cell, where the electrons go to, and the other that oxides are at the anode of the cell.
The standard reduction potentials from Al(s) and Cu(s) are, respectively, -1.66V and +0.15V, so the half-cell of Cu(s) in Cu(NO₃)₂(aq) is the cathode.
