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o-na [289]
4 years ago
5

Which expression is equal to 5y^3÷5y^-2

Mathematics
1 answer:
Misha Larkins [42]4 years ago
5 0

Answer:

5y^3/5y^-2 = y^5

Step-by-step explanation:

5y^3/5y^-2

as 5 is both in numerator and denominator it will get cancelled so we have now expression

y^3/y^-2

we will use  law of indices wherein if there is

a^x/a^y = a^(x-y)

which means that if the base is same in numerator and denominator then we have to subtract the power of denominator from numerator to get the reduced form using this concept

here power in numerator is 3 and power in denominator  is -2

hence we will be subtracting -2 from 3

y^3/y^-2 = y^(3-(-2) = y^(3+2) = y^5

Thus,

5y^3/5y^-2 = y^5

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Which quotient is equivalent to the mixed number
rusak2 [61]
To answer this question you will convert the mixed number into an improper fraction. To do this you have to understand that The two wholes in the mix number each equal 3/3. This would give you 6/3 for the two wholes. Add the 6/3 to the 2/3 that are there in the fraction, and you will have 8/3. the quotient(answer to a division problem) is 8/3 as a fraction.
8 0
4 years ago
Help me please<br> Find the value of x.
Otrada [13]

Answer:

110

Step-by-step explanation:

180-35-35

8 0
3 years ago
What are the zeros of the function f(x) = x2 + 5x + 5 written in simplest radical form?
RideAnS [48]

Step-by-step explanation:

The function is as follows :

f(x) = x^2 + 5x + 5

We need to find the zeroes of the function in the simplest radical form.The zero of the above function is given by :

x=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}

Here,

b = 5

a = 1

c = 5

So,

x=\dfrac{-5\pm \sqrt{5^2-4\times 1\times 5} }{2(1)}\\\\x=\dfrac{-5\pm \sqrt{25-20} }{2(1)}\\\\x=\dfrac{-5\pm \sqrt{5} }{2}

Hence, the correct option is (c).

6 0
4 years ago
5(4x+9)=-50+15 solve the equation
Alenkinab [10]

Answer:

x = -4

Step-by-step explanation:

5(4x+9)=-50+15

20x+45=-50+15

20x+45=-35

      -45  -45

20x=-80

/20   /20

x=-4

7 0
3 years ago
Item 15 Your math class is collecting canned food for a local food drive. The goal is to collect at least 130 cans but no more t
Margarita [4]

For this case, the first thing we must do is define variables.

We have then:

n: number of cans that each student must bring

We know that:

The teacher will bring 5 cans

There are 20 students in the class

At least 105 cans must be brought, but no more than 205 cans

Therefore the inequation of the problem is given by:

Answer:

105 <u><</u> 20n + 5 <u><</u> 205

the possible numbers n of cans that each student should bring in is:

105 <u><</u> 20n + 5 <u><</u> 205

8 0
3 years ago
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