All categories

2 years ago

Help me please Find the value of x.

Mathematics

1 answer:

Otrada [13]2 years ago

8 0

Answer:

110

Step-by-step explanation:

180-35-35

You might be interested in

Read The question and give Me The answer for number 17

Andre45 [30]

Answer:

( - 5,2);( -2, -3); (4, -1)

So your answer is: A.

3 0

2 years ago

Read 2 more answers

Michael is a basketball player who regularly shoots sets of 2 free-throws. Suppose that each shot has probability 0.60. , point,

Sati [7]

Answer:

0.1306

Step-by-step explanation:

This is a binomial distribution problem

Binomial distribution function is represented by

P(X = x) = ⁿCₓ pˣ qⁿ⁻ˣ

n = total number of sample spaces = number of free throws

x = Number of successes required = 6

p = probability of success = 0.60

q = probability of failure = 1 - 0.60 = 0.40

P(X = 6) = ⁷C₆ (0.6)⁶ (0.4)⁷⁻⁶ = 0.1306368 = 0.1306

Hope this Helps!!!

4 0

2 years ago

Find the product of all real values of r for which 1/2x=r-x/7

Dahasolnce [82]

Answer:

$r = \±\sqrt{14$

$Product = -14$

Step-by-step explanation:

Given

$\frac{1}{2x} = \frac{r - x}{7}$

Required

Find all product of real values that satisfy the equation

$\frac{1}{2x} = \frac{r - x}{7}$

Cross multiply:

$2x(r - x) = 7 * 1$

$2xr - 2x^2 = 7$

Subtract 7 from both sides

$2xr - 2x^2 -7= 7 -7$

$2xr - 2x^2 -7= 0$

Reorder

$- 2x^2+ 2xr -7= 0$

Multiply through by -1

$2x^2 - 2xr +7= 0$

The above represents a quadratic equation and as such could take either of the following conditions.

(1) No real roots:

This possibility does not apply in this case as such, would not be considered.

(2) One real root

This is true if

$b^2 - 4ac = 0$

For a quadratic equation

$ax^2 + bx + c = 0$

By comparison with $2x^2 - 2xr +7= 0$

$a = 2$

$b = -2r$

$c =7$

Substitute these values in $b^2 - 4ac = 0$

$(-2r)^2 - 4 * 2 * 7 = 0$

$4r^2 - 56 = 0$

Add 56 to both sides

$4r^2 - 56 + 56= 0 + 56$

$4r^2 = 56$

Divide through by 4

$r^2 = 14$

Take square roots

$\sqrt{r^2} = \±\sqrt{14$

$r = \±\sqrt{14$

Hence, the possible values of r are:

$\sqrt{14$ or $-\sqrt{14$

and the product is:

$Product = \sqrt{14} * -\sqrt{14}$

$Product = -14$

8 0

2 years ago

Simplify the expression <br> 3^0

Art [367]

Answer:

Step-by-step explanation:

3^0

Any number ( besides 0) raised to the zero power is 1

5 0

3 years ago

Read 2 more answers

PLS need help 0.85= y/0.8 - 0.1 find y

zvonat [6]

Answer:0.76

Step-by-step explanation:

5 0

1 year ago