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alisha [4.7K]
3 years ago
15

For the isopropyl alcohol solution, what types of intermolecular forces would be experienced by the FD and; C Red 40, Blue 1 and

Yellow 5 and the solution
Chemistry
1 answer:
IgorLugansk [536]3 years ago
4 0

Answer:

Hi

Isopropyl alcohol is a colorless, flammable liquid with an intense smell and miscible with water. It is an isomer of 1-propanol. It is obtained by means of a hydration reaction with propylene. It is also produced by hydrogenation of acetone. There are two main ways for the process of hydrating propylene: indirect hydration by sulfuric acid and direct hydration. The type of bond that presents hydrogen bonds and dipole-dipole forces.

Explanation:

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i dont really know i will find some more information on that in about 5 minutes

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Which mixture is heterogeneous?
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I guess it is D, bc heterogeneous means a mixture that’s not uniform in structure
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3 years ago
Which reactions are oxidation-reduction reactions? Check all that apply
tia_tia [17]

2 Na + Cl₂ → 2 NaCl

Cu + 2 AgNO₃ → Cu(NO₃)₂ + 2 Ag

CH₄ + 2 O₂ → CO₂ + 2 H₂O​

are oxidation-reduction reactions

Explanation:

In the oxidation-reduction reaction there is a component which accept electrons and it is reduced and another component which donates electrons and it is oxidized.

Now in the case of the reaction of copper (Cu) with silver nitrate (AgNO₃):

Cu + 2 AgNO₃ → Cu(NO₃)₂ + 2 Ag

Cu⁰ with a oxidation number 0 donates 2 electrons⁻ and is transformed in Cu⁺² with the oxidation number 2+.

Ag⁺ with a oxidation number 1+ accepts 1 electron⁻ and is transformed in Ag with the oxidation number 0.

In the case of CH₄ + 2 O₂ → CO₂ + 2 H₂O​ reaction we have:

C⁴⁻ with a oxidation number +4 donates 8 electrons⁻ and is transformed in C⁴⁺ with the oxidation number 4+.

O⁰ with a oxidation number 0 accepts 2 electrons⁻ and is transformed in O²⁻ with the oxidation number 2-.

And in the case of 2 Na + Cl₂ → 2 NaCl reaction we have:

Na⁰ with a oxidation number 0 donates 1 electron⁻ and is transformed in Na⁺ with the oxidation number 1+.

Cl⁰ with a oxidation number 0 accepts 1 electron⁻ and is transformed in Clwith the oxidation number 1-.

Learn more about:

oxidation-reduction reactions

brainly.com/question/4222605

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4 0
3 years ago
A gas has an initial volume of 52.3 L at 273 Kelvin. What is its temperature when the volume reaches 145.7 L?
erastovalidia [21]

Answer:

\boxed {\boxed {\sf 761 \ K}}

Explanation:

We are asked to find the new temperature of a gas after a change in volume. We will use Charles's Law, which states the volume of a gas is directly proportional to the temperature. The formula for this law is:

\frac {V_1}{T_1}= \frac{V_2}{T_2}

The volume is initially 52.3 liters at a temperature of 273 Kelvin.

\frac {52.3 \ L}{273 \ K}= \frac{V_2}{T_2}

The volume reaches 145.7 liters at an unknown temperature.

\frac {52.3 \ L}{273 \ K}= \frac{145.7 \ L }{T_2}

We are solving for the new temperature, so we must isolate the variable T₂.  Cross multiply. Multiply the first numerator and second denominator, then the first denominator and second numerator.

52.3 \ L * T_2 = 273 \ K * 145.7 \ L

Now the variable is being multiplied by 52.3 liters. The inverse of multiplication is division. Divide both sides by 52.3 L.

\frac {52.3 \ L * T_2 }{52.3 \ L}=\frac{ 273 \ K * 145.7 \ L}{52.3 \ L}

T_2=\frac{ 273 \ K * 145.7 \ L}{52.3 \ L}

The units of liters cancel.

T_2=\frac{ 273 \ K * 145.7 }{52.3 }

T_2 = 760.5372849 \ K

The original measurements have at least 3 significant figures, so our answer must have 3. For the number we found, that is the ones place. The 5 in the tenths place tells us to round the 0 up to a 1.

T_2 \approx 761 \ K

When the volume reaches 145.7 liters, the temperature is <u>761 Kelvin.</u>

8 0
3 years ago
Which is not a formula for a diatomic molecule? N2 O3 He
Sergeu [11.5K]
He because nitrogen and ozone is a molecule but helium is atom
7 0
4 years ago
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