All categories

3 years ago

Why are some alkali metals stored under oil?

Chemistry

2 answers:

Dahasolnce [82]3 years ago

6 0

due to there reactive rate?

Fiesta28 [93]3 years ago

5 0

Alkali metals are stored under oil because of their high reactivity. Alkali metals must be stored under oil to prevent reaction with air.

You might be interested in

Why would someone weigh less on Pluto?

Dvinal [7]

Because of gravity not pulling you down

3 0

4 years ago

Balance the redox reaction Al(s) + MnO4^- (aq) --> MnO2 (s) + Al(OH)4^- (aq) in aqueous basic solution

GREYUIT [131]

Answer:

Al + MnO4- + 2H2O → Al(OH)4- + MnO2

Explanation:

First of all, we out down the skeleton equation;

Al + MnO4- → MnO2 + Al(OH)4-

Secondly, we write the oxidation and reduction equation in basic medium;

Oxidation half equation:Al + 4H2O + 4OH- → Al(OH)4- + 4H2O + 3e-

Reduction half equation:MnO4- + 4H2O + 3e- → MnO2 + 2H2O + 4OH-

Thirdly, we add the two half reactions together to obtain:

Al + MnO4- + 8H2O + 4OH- + 3e- → Al(OH)4- + MnO2 + 6H2O + 3e- + 4OH-

Lastly, cancel out species that occur on both sides of the reaction equation;

Al + MnO4- + 8H2O→ Al(OH)4- + MnO2 + 6H2O

The simplified equation now becomes;

Al + MnO4- + 2H2O → Al(OH)4- + MnO2

4 0

3 years ago

Write the ions that result from the dissociation of na2s

Sveta_85 [38]

2Na^+ and S^2-

(sodium cation and sulfide anion)

5 0

4 years ago

If the smallest markings on a ruler are one tenth (1/10) of a centimeter, which of the following measurements could be recorded

makkiz [27]

I think it should be A

4 0

4 years ago

Read 2 more answers

What is the osmolarity of .00001 grams (0.1 mg%) of ethanol (does not dissociate) in one liter?

MrMuchimi

Explanation:

As it is known that non-electrolytes do not dissociate. Therefore, molarity of such a solution is equal to the osmolarity of solution.

As, molar mass of ethanol = 46.07 g/mol

Therefore, no. of moles of ethanol will be calculated as follows.

No. of moles = $\frac{mass}{\text{molar mass}}$

= $\frac{0.00001 g}{46.07 g/mol}$

= $2.17 \times 10^{-7}$ mol

As, molarity is moles of solute in liter of solution. Hence, molarity of ethanol is as follows.

Molarity = $\frac{\text{no. of moles}}{volume}$

= $\frac{2.17 \times 10^{-7} mol}{1 L}$

= $2.17 \times 10^{-7}$ mol/L

Since, for the given solution Molarity = osmolarity

Thus, we can conclude that osmolarity of .00001 grams (0.1 mg%) of ethanol in 1 L is $2.17 \times 10^{-7}$ osmol/L.

8 0

3 years ago