Answer: h(x) = 3*x^2 - 7*x + 8
Step-by-step explanation:
The rate of change of a function is equal to the derivate:
remember that a derivate of the form:
k(x) = a*x^n is k'(x) = n*a*x^(n-1)
Then we have:
f(x) = 2*x - 10
f'(x) = 1*2* = 2
g(x) = 16*x - 4
g'(x) = 1*16 = 16
h(x) = 3*x^2 - 7*x + 8
h'(x) = 2*3*x - 1*7 = 6*x - 7
So the only that increases as x increases is h(x), this means that the greates rate of change as x approaches inffinity is the rate of change of h(x)
Answer:
880
Step-by-step explanation:
2/5 times 2200
Answer:
The first statement is true.
Step-by-step explanation:
The function is f(x) = - (x + 6)(x + 2)
⇒ f(x) = - x² - 8x - 12
Now, condition for a function f(x) to be increasing at x = a is f'(a) > 0.
Now, f(x) = - x² - 8x - 12
⇒ f'(x) = -2x - 8 {Differentiating with respect to x}
Now, f'(a) = -2a - 8 {Here a can be any real value}
And, the condition for increasing function at x = a is
- 2a - 8 > 0
⇒ - 2a > 8
⇒ a < - 4
Therefore, the first statement is true i.e. the function is increasing for all real values of x where x < – 4. (Answer)
Answer:
x=27
Step-by-step explanation:
