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zhuklara [117]
3 years ago
11

The kinetic energy of the free electron at the point of collision is higher if the atom is closer to the source of electrons

Physics
1 answer:
katen-ka-za [31]3 years ago
3 0
True the only way to emit ur proton is if there are ground electrical
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You stand on a straight desert road at night and observe a vehicle approaching. This vehicle is equipped with two small headligh
spayn [35]

To solve this problem we will apply the concepts related to Reyleigh's criteria. Here the resolution of the eye is defined as 1.22 times the wavelength over the diameter of the eye. Mathematically this is,

\theta = \frac{1.22 \lambda }{D}

Here,

D is diameter of the eye

D = \frac{1.22 (539nm)}{5.11 mm}

D= 1.287*10^{-4}m

The angle that relates the distance between the lights and the distance to the lamp is given by,

Sin\theta = \frac{d}{L}

For small angle, sin\theta = \theta

sin \theta = \frac{d}{L}

Here,

d = Distance between lights

L = Distance from eye to lamp

For small angle sin \theta = \theta

Therefore,

L = \frac{d}{sin\theta}

L = \frac{0.691m}{1.287*10^{-4}}

L = 5367m

Therefore the distance is 5.367km.

4 0
4 years ago
Jim thinks that he can throw a baseball six meters per second. What does the six meters refer to?
SVETLANKA909090 [29]

Answer:

Six meters refers to the distance the baseball travels in one second.

Explanation:

6 m/s means that every second, the baseball travels 6m. So, 6 meters is the distance traveled in one second.

3 0
3 years ago
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How much does the speed of a car increase if it accelerates
Nata [24]

Answer:

12.5 m/s

Explanation:

a = Δv / Δt

2.5 m/s² = Δv / 5 s

Δv = 12.5 m/s

4 0
3 years ago
The periodic table was developed in order to group and organize elements with similar physical and chemical properties.
nadezda [96]
Your answer to this question is A halogens. 
6 0
4 years ago
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Santa doesn't want to push a 25.0 kg wooden box across a wooden floor with a uk of 0.20 at
scZoUnD [109]

Answer:

49 N

Explanation:

In order to move the box at constant speed, the acceleration of the box must be zero (a=0): this means, according to Newton's second law,

F = ma

that the net force acting on the box, F, must be zero as well.

Here there are two forces acting on the box in the horizontal direction while it is moving:

- The force of push applied by the guy, F

- The frictional force, F_f

For an object moving on a flat surface, the frictional force is given by

F_f = \mu_k mg

where

\mu_k is the coefficient of friction

m is the mass of the box

g is the acceleration of gravity

So the equation of the forces becomes

F-\mu_k mg = 0

And substituting:

\mu_k = 0.20\\m = 25.0 kg\\g = 9.8 m/s^2

We find the force that must be applied by the guy:

F=\mu_k mg = (0.20)(25.0)(9.8)=49 N

6 0
3 years ago
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