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2 years ago

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classroom and draw an approxim object Three forces are acting on an object (Figure 1.32) which is in equilibrium. Determine forc

e A 1200 N Force A 51 39 42.00 1400 N Figure 1.32 Three forces, acting on

1 answer:

kumpel [21]2 years ago

6 0

I’m not good with physics but I’m good with the theory what goes up must come down

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How long does a car (1000 kg) have a speed of 30 m/s from a rest if the engine power is 10kw

Lemur [1.5K]

Answer: 90.1 s

Explanation:

Use equation for power:

P=F*V

Use eqation for force:

F=ma

F---force

V---velocity

Vr=om/s

V=30m/s

m=1000kg

P=10000W

---------------------------

P=FV

F=P/V

F=10000W/30m/s

F=333.33N

Use equation for force to find accelartaion.

F=ma

a=F/m

a=333.33N/1000kg

a=0.333 m/s²

Use equation for accelaration to find out time:

a=(V-Vs)/t

t=(V-Vs)/a

t=(30m/s)/(0.333m/s²)

t=90.09 s≈90.1 s

------------------------

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3 years ago

Who was the first scientist to question the idea that atoms were uncuttable

gizmo_the_mogwai [7]

Answer:

Democritus

Explanation:

He called these "uncuttable" pieces atomos. This is where the modern term atom comes from. Democritus first introduced the idea of the atom almost 2500 years ago.

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3 years ago

What is the net charge of a copper atom if it gains 2 electrons?

Alex_Xolod [135]

If an atom gains electrons, it develops a negative charge equal to the number of electrons gained.
So the net charge on the copper atom which gained 2 electrons will be -2.

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3 years ago

Hunter works to fix wires and paneling. Hunter is a(n)

Serjik [45]

Answer:

Hunter is a electrician

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3 years ago

Read 2 more answers

When you jump from an elevated position you usually bend your knees upon reaching the ground. By doing this, you make the time o

dsp73

Answer:

c. about 1/10 as great.

Explanation:

While jumping form a certain height when we bend our knees upon reaching the ground such that the time taken to come to complete rest is increased by 10 times then the impact force gets reduced to one-tenth of the initial value when we would not do so.

This is in accordance with the Newton's second law of motion which states that the rate of change in velocity is directly proportional to the force applied on the body.

Mathematically:

$F\propto\frac{d}{dt} (p)$

$\Rightarrow F=\frac{d}{dt} (m.v)$

since mass is constant

$F=m\frac{d}{dt}v$

when $dt=10t$

then,

$F'=m.\frac{v}{10\times t}$

$F'=\frac{1}{10} \times \frac{m.v}{t}$

$F'=\frac{F}{10}$ the body will experience the tenth part of the maximum force.

where:

$\frac{d}{dt} =$ represents the rate of change in dependent quantity with respect to time

$p=$ momentum

$m=$ mass of the person jumping

$v=$ velocity of the body while hitting the ground.

7 0

3 years ago