Ask question

Ask question

All categories

3 years ago

5

classroom and draw an approxim object Three forces are acting on an object (Figure 1.32) which is in equilibrium. Determine forc

e A 1200 N Force A 51 39 42.00 1400 N Figure 1.32 Three forces, acting on

1 answer:

kumpel [21]3 years ago

6 0

I’m not good with physics but I’m good with the theory what goes up must come down

You might be interested in

An object has a mass of 13.5 kilograms. What force is required to accelerate it to a rate of 9.5 m/s2?

Zigmanuir [339]

Force can be expressed as the product of mass and acceleration. Mathematically, that's F = m(a). Plugging the given into the equation, we have F = (13.5 kg)(9.5 m/s²) = 128.3 kg.m/s² or 128.3 N<span>. </span>

4 0

3 years ago

Why is a minimum of three seismic stations needed to find the epicenter of an earthquake?

vazorg [7]

Each station can detect how far away the epicenter was. So each station basically has a circle made of possible epicenters. When you have three, you narrow it down to one, final point.

5 0

3 years ago

The force of attraction between a -130.0 C and +180.0 C charge is 8.00 N. What is the separation between these two charges in me

kondaur [170]

Answer with Explanation:

The force of attraction between 2 charges of magnitude $q_1,q_2$ separated by a distance 'r' is given by

$F=\frac{1}{4\pi \epsilon _o}\frac{q_1\times q_2}{r^2}=k\frac{q_1\times q_2}{r^2}$

where

$\epsilon _o$ is a constant known as permitivity of free space

$k=9\times 10^{9}Nm^2/C^2$

Applying the given values in the above relation we get

$8=9\times 10^{9}\times \frac{130\times 180}{r^{2}}\\\\r^{2}=\frac{9\times 10^{9}\times 130\times 180}{8}\\\\r^{2}=26325\times 10^{9}\\\\\therefore r=\sqrt{26325\times 10^{9}}=5.131\times 10^{6}meters$

5 0

3 years ago

Define the physics quantity of work

umka2103 [35]

Explanation:

Work done is the force applied to move a body through a specific or particular direction.

It is also the difference in the amount of energy expended in using an effort.

Work done is given as;

Work done = F x d CosФ

F is the force applied

d is the displacement

Ф is the angle

The unit of work done is in Joules.

5 0

3 years ago

A graduated cylinder.measures 15.3 mL. Convert this measurement to DaL

ololo11 [35]

Answer:

0.000153DaL

Explanation:

We have been given:

15.3mL to convert to DaL

DaL is a unit of volume which indicates a decaliter.

This implies that;

1 Da L = 1 x 10²L

So:

1 mL = 1 x 10⁻³L

So 15.3mL will give 15.3 x 10⁻³L

So;

1 x 10²L = 1 DaL

15.3 x 10⁻³L will give $\frac{15.3 x 10^{-3} }{1 x 10^{2} }$ = 15.3 x 10⁻⁵DaL

Therefore, this is 0.000153DaL

5 0

3 years ago