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2 years ago

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classroom and draw an approxim object Three forces are acting on an object (Figure 1.32) which is in equilibrium. Determine forc

e A 1200 N Force A 51 39 42.00 1400 N Figure 1.32 Three forces, acting on

1 answer:

kumpel [21]2 years ago

6 0

I’m not good with physics but I’m good with the theory what goes up must come down

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Two asteroids identical to those above collide at right angles and stick together; i.e, their initial velocities were perpendicu

11111nata11111 [884]

Answer:

velocity = 62.89 m/s in 58 degree measured from the x-axis

Explanation:

Relevant information:

Before the collision, asteroid A of mass 1,000 kg moved at 100 m/s, and asteroid B of mass 2,000 kg moved at 80 m/s.

Two asteroids moving with velocities collide at right angles and stick together. Asteroid A initially moving to right direction and asteroid B initially move in the upward direction.

Before collision Momentum of A = 1000 x 100 = $10^5$ kg - m/s in the right direction.

Before collision Momentum of B = 2000 x 80 = 1.6 x $10^5$ kg - m/s in upward direction.

Mass of System of after collision = 1000 + 2000 = 3000 kg

Now applying the Momentum Conservation, we get

Initial momentum in right direction = final momentum in right direction = $10^5$

And, Initial momentum in upward direction = Final momentum in upward direction = 1.6 x $10^5$

So, $V_x = \frac{10^5}{3000}$ = $\frac{100}{3}$ m/s

and $V_y=\frac{160}{3}$ m/s

Therefore, velocity is = $\sqrt{V_x^2 + V_y^2}$

= $\sqrt{(\frac{100}{3})^2 + (\frac{160}{3})^2}$

= 62.89 m/s

And direction is

tan θ = $\frac{V_y}{V_x}$ = 1.6

therefore, $\theta = \tan^{-1}1.6$

= $58 ^{\circ}$ from x-axis

4 0

2 years ago

Suppose a wheel with a tire mounted on it is rotating at the constant rate of 2.59 times a second. A tack is stuck in the tire a

Vesna [10]

Answer:

Tangential speed=5.4 m/s

Radial acceleration= $88.6m/s^2$

Explanation:

We are given that

Angular speed=2.59 rev/s

We know that

1 revolution= $2\pi rad$

2.59 rev= $2\pi\times 2.59=5.18\pi=5.18\times 3.14=16.27 rad/s$

By using $\pi=3.14$

Angular velocity= $\omega=16.27rad/s$

Distance from axis=r=0.329 m

Tangential speed= $r\omega=16.27\times 0.329=5.4m/s$

Radial acceleration= $\frac{v^2}{r}$

Radial acceleration= $\frac{(5.4)^2}{0.329}=88.6m/s^2$

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2 years ago

PLS DO THIS FOR ME I NEED DONE ASAP

mart [117]

G g j inj g f d t u u i

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2 years ago

Why do astronauts' weights differ in space?

OLga [1]

Answer:

There is less gravitational force in space.

Explanation:

Gravity doesn't exist as it does on Earth. Earth's gravity is as 6 times stronger as it is on the moon.

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2 years ago

Que hace falta para descubrir hasta que punto todas y todos somos diferentes y ver que eso, más bien es valioso y positivo

lara [203]

Answer:

Para descubrir que las diferencias entre las personas son valiosas y positivas para la creación de sociedades más diversas y enriquecidas culturalmente, es necesario valorar las condiciones personales de cada persona de modo positivo, abandonando posturas discriminatorias como el racismo o la xenofobia, para así aceptar la diversidad social. Además, debe fomentarse el respeto por la opinión y la visión del otro, para que las personas no tomen al que piensa diferente como un adversario al que hay que confrontar. Solo así podrá lograrse una sociedad más diversa y respetuosa de las diferencias, sean culturales, étnicas o intelectuales.

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2 years ago