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CaHeK987 [17]
3 years ago
11

Think about the process of heating water, the heating and upward motion of hot steam and air, and the spiral spinning. For these

events, list each form of energy associated with the heat source, the water, the steam and air, and the spiral.
Kinetic Energy Forms:
-Motion Energy
-Thermal Energy
-Electric Energy
-Vibrational Energy
-Radiant Energy

Potential Energy Forms:
-Gravitational Potential Energy
-Elastic Potential Energy
-Chemical Potential Energy
-Electric Potential Energy
-Magnetic Potential Energy
-Nuclear Potential Energy
Physics
2 answers:
olya-2409 [2.1K]3 years ago
7 0

Answer:

thermal and gravitational potential

Explanation:

Sloan [31]3 years ago
4 0

Answer:

A uniform ladder of mass and length leans at an angle against a frictionless wall .If the coefficient of static friction between the ladder and the ground is , determine a formula for the minimum angle at which the ladder will not slip.

Explanation:A uniform ladder of mass and length leans at an angle against a frictionless wall .If the coefficient of static friction between the ladder and the ground is , determine a formula for the minimum angle at which the ladder will not slip.

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What is the magnitude of the electric force of attraction between an iron nucleus (q=+26e) and its innermost electron if the dis
iris [78.8K]

Answer:

The magnitude of the force on an electron is 0.069 N.

Explanation:

Given that,

Distance between 1.70 A from the plutonium nucleus, d=1.5\times 10^{-12}\ m

The number of electron in iron nucleus is +26e.

To find,

The magnitude of the force between an iron nucleus.

Solution,

Total charge in the plutonium nucleus is, q=26\times 1.6\times 10^{-19}=4.16\times 10^{-18}\ C. The electric force between charges is given by :

F=\dfrac{kq^2}{d^2}

F=\dfrac{9\times 10^9\times (4.16\times 10^{-18})^2}{(1.5\times 10^{-12})^2}

F = 0.069 N

So, the magnitude of the force on an electron is 0.069 N. Hence, this is the required solution.

4 0
3 years ago
A river flows due south with a speed of 2.0 m/s .You steer a motorboat across the river; your velocity relative to the water is
mihalych1998 [28]

Answer:

a) v_m =\sqrt{v^2_x + v^2_y} = \sqrt{(2m/s)^2 +(4.8 m/s)^2}= 5.2 m/s

b) \theta= tan^{-1} \frac{v_y}{v_x} = tan^{-1} (\frac{2}{4.8})= 22.62 degrees and on this case to the South of the East.

c)t= \frac{w}{v_m}= \frac{600m}{4.8 m/s}= 125 s

d) Y = 2 m/s * 125 s = 250m

So it would be 250 to the South

Explanation:

Part a

For this case the figure attached shows the illustration for the problem.

We know that v_y = 2 m/s represent the velocity of the river to the south.

We have the velocity of the motorboard relative to the water and on this case is V_x= 4.8 m/s

And we want to find the velocity of the motord board relative to the Earth v_m

And we can find this velocity from the Pythagorean Theorem.

v_m =\sqrt{v^2_x + v^2_y} = \sqrt{(2m/s)^2 +(4.8 m/s)^2}= 5.2 m/s

Part b

We can find the direction with the following formula:

\theta= tan^{-1} \frac{v_y}{v_x} = tan^{-1} (\frac{2}{4.8})= 22.62 degrees and on this case to the South of the East.

Part c

For this case we can use the following definition

D = Vt

The distance would be D = w = 600 m and the velocity V = 4.8m/s and if we solve for t we got:

t= \frac{w}{v_m}= \frac{600m}{4.8 m/s}= 125 s

Part d

For this case we can use the same definition but now using the y compnent we have:

Y = v_y t

And replacing we got:

Y = 2 m/s * 125 s = 250m

So it would be 250 to the South

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What is a characteristic of weight &lt;br /&gt;<br>I need it please answer it​
Marta_Voda [28]

Answer:

Weight is a consequence of the universal law of gravitation

Explanation:

Weight, gravitational force of attraction on an object, caused by the presence of a massive second object, such as the Earth or Moon. Weight is a consequence of the universal law of gravitation: any two objects, because of their masses, attract each other with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.

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Describe how Ubuntu could help to lack of basic services challenges<br>​
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