The probability that the transistor will last between 12 and 24 weeks is 0.424
X= lifetime of the transistor in weeks E(X)= 24 weeks
O,= 12 weeks
The anticipated value, variance, and distribution of the random variable X were all provided to us. Finding the parameters alpha and beta is necessary before we can discover the solutions to the difficulties.
X~gamma(
)
E(X)= 
= 
=6 weeks
V(x)= 
=24/6= 4
Now we can find the solutions:
The excel formula used to create Figure one is as follows:
=gammadist(X, , , False)
P(
)
P(
)
P(
)
P= 0.424
Therefore, probability that the transistor will last between 12 and 24 weeks is 0.424
To learn more about probability click here:
brainly.com/question/11234923
#SPJ4
0.4×29.95
=11.98 so your answer is 11 dollars and 98 cents
Answer:
Step-by-step explanation:
Given the mean is 3.2, standard deviation is 0.8 and the sample size is 64.
-We calculate the probability of a mean of 3.4 as follows:
#First determine the z-value:
#We then determine the corresponding probability on the z tables:
Hence, the probability of obtaining a sample mean this large or larger is 0.0228
20 ÷ 2 (5,5)
20 ÷ 2 (25)
20 ÷ 50
.4
Answer:
BC + CD = BD
Step-by-step explanation:
The segment addition postulate tells you that when a segment is divided into two parts, the sum of the lengths of the first part of the divided segment and the second part of the divided segment will be equal to the length of the whole segment.
If point C divides segment BD into BC and CD, then the sum of those two segments will match the whole.
