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3 years ago

How do u work out what fraction is equal to 1/8

1 answer:

7 0

If the number on the bottom of the fraction is 8 times the size
of the number on top, then the fraction is equal to 1/8 .

Examples:

100 / 800

20 / 160

8 / 64

You might be interested in

The square root of 27 lies between which two whole numbers

Agata [3.3K]

Answer:

5 and 6

Step-by-step explanation:

The square root of 27 is 5.19615242271 , which is more than 5 but less then 6, therefore is between 5 and 6.

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<em>Hope this helped (: Can you please mark as brainliest?</em>

7 0

3 years ago

18x-(-3x+9)help!!! Please

Anon25 [30]

Answer:

21x - 9

Step-by-step explanation:

3 0

3 years ago

How many terms are there in the sequence 1, 8, 28, 56, ..., 1 ?

BabaBlast [244]

Answer:

9 terms

Step-by-step explanation:

Given:

1, 8, 28, 56, ..., 1

Required

Determine the number of sequence

To determine the number of sequence, we need to understand how the sequence are generated

The sequence are generated using

$\left[\begin{array}{c}n&&r\end{array}\right] = \frac{n!}{(n-r)!r!}$

Where n = 8 and r = 0,1....8

When r = 0

$\left[\begin{array}{c}8&&0\end{array}\right] = \frac{8!}{(8-0)!0!} = \frac{8!}{8!0!} = 1$

When r = 1

$\left[\begin{array}{c}8&&1\end{array}\right] = \frac{8!}{(8-1)!1!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8$

When r = 2

$\left[\begin{array}{c}8&&2\end{array}\right] = \frac{8!}{(8-2)!2!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} =2 8$

When r = 3

$\left[\begin{array}{c}8&&3\end{array}\right] = \frac{8!}{(8-3)!3!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56$

When r = 4

$\left[\begin{array}{c}8&&4\end{array}\right] = \frac{8!}{(8-4)!4!} = \frac{8!}{4!3!} = \frac{8 * 7 * 6 * 5 * 4!}{4! *4*3* 2 *1} = \frac{8 * 7 * 6*5}{4*3 *2 *1} = 70$

When r = 5

$\left[\begin{array}{c}8&&5\end{array}\right] = \frac{8!}{(8-5)!5!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56$

When r = 6

$\left[\begin{array}{c}8&&6\end{array}\right] = \frac{8!}{(8-6)!6!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} = 28$

When r = 7

$\left[\begin{array}{c}8&&7\end{array}\right] = \frac{8!}{(8-7)!7!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8$

When r = 8

$\left[\begin{array}{c}8&&8\end{array}\right] = \frac{8!}{(8-8)!8!} = \frac{8!}{8!0!} = 1$

The full sequence is: 1,8,28,56,70,56,28,8,1

And the number of terms is 9

3 0

3 years ago

Mary is preparing for her college entrance exams in a practice test she answered 12 problems in 30 minutes at this rate how many

kap26 [50]

Answer:

40 problems in 100 minutes

Step-by-step explanation:

This is a ratio problem.

You first divide 30 minutes by three to get how many problems she can do in 10 minutes. What you do to one side you do to the other side. So then, you should have 4 problems in 10 minute. Then, you multiply 10 by 10 and 4 by 10 to get 40 problems in 100 minutes.

6 0

4 years ago

Fernando bought a jacket for 185 and sold it for 1 1/2 what he paid. Marisol spent 1/5 as much as Fernando on the same jacket bu

avanturin [10]

Answer:

Marisol made $138.75 on the sale of the jacket

Step-by-step explanation:

First we are told that Fernando bought a jacket for $185, and sold it for 1 1/12 what he paid.

Therefore, 1 1/2 of 185;

= 1.5 × 185 = $277.5

Therefore, Fernando sold the Jacket for $277.5

Next, we are told that:

Marisol spent 1/5 as much as Fernando on the same jacket

This means that Marisol spent 1/5 of $185 on the jacket

= 1/5 × 185 = 0.2 × 185 = $37

Therefore, Marisol spent $37 to buy the same jacket

Next, Marisol sold the jacket for 1/2 as much as Fernando. Since Fernando sold the Jacket for $277.5, Marisol sold the jacket for 1/2 of 277.5, and this is calculated as:

1/2 of 277.5 = 0.5 × 277.5 = 138.75

Therefore, Marisol made $138.75 on the sale of the jacket.

6 0

3 years ago