$\bf 10\cdot [2+(24-8)]\div 4\implies \stackrel{\mathbb{PEMDAS}}{10\cdot [2+(16)]\div 4}\implies 10\cdot [18]\div 4
\\\\\\
180\div 4\implies 45$

recall, peMDas, Multiplication and Division, from left-to-right.

7 0

3 years ago

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The diagram shows a row of four identical tiles, each in the shape of an isosceles trapezoid. What is the area of one tile?

VMariaS [17]

I saw the image that accompanied this problem.

4 identical isosceles trapezoid forming 2 parallelogram.
1 parallelogram has a base of 16 inches and its height is 10 inches.

We need to get the area of the parallelogram and multiply it by 2 before dividing it into 4 to get the area of each isosceles trapezoid.

Area of a parallelogram = base * height
A = 16 in x 10 in = 160 in²

160 in² x 2 parallelogram = 320 in²
320 in² / 4 tiles = 80 in²

The area of one tile is 80 square inches.

8 0

3 years ago

A particle is moving along the curve y= 5 \sqrt{4 x + 1}. As the particle passes through the point (2, 15), its x-coordinate inc

marysya [2.9K]

$y = 5 \sqrt{4x + 1}$

$y = 5(2 x^{ \frac{1}{2} } + 1)$

$y = 5(2 x^{ \frac{1}{2} }) + 5(1)$

$y = 10 x^{ \frac{1}{2} } + 5$

7 0

3 years ago