This isn’t twitter but anyways the answer is 29
1.)
<span>((i <= n) && (a[i] == 0)) || (((i >= n) && (a[i-1] == 0))) </span>
<span>The expression will be true IF the first part is true, or if the first part is false and the second part is true. This is because || uses "short circuit" evaluation. If the first term is true, then the second term is *never even evaluated*. </span>
<span>For || the expression is true if *either* part is true, and for && the expression is true only if *both* parts are true. </span>
<span>a.) (i <= n) || (i >= n) </span>
<span>This means that either, or both, of these terms is true. This isn't sufficient to make the original term true. </span>
<span>b.) (a[i] == 0) && (a[i-1] == 0) </span>
<span>This means that both of these terms are true. We substitute. </span>
<span>((i <= n) && true) || (((i >= n) && true)) </span>
<span>Remember that && is true only if both parts are true. So if you have x && true, then the truth depends entirely on x. Thus x && true is the same as just x. The above predicate reduces to: </span>
<span>(i <= n) || (i >= n) </span>
<span>This is clearly always true. </span>
I think that the answer is packets.
A partial dependency exists.
We have two types of dependency. The partial dependency and the transitive dependency.
The answer here is partial dependency. It occurs when the attribute only depends on some parts of the element. In such attribute, the primary key is the determinant.
It can be shown as;
XY→WZ , X→W and XY is the primary key or the only candidate key
Read more at brainly.com/question/9588869?referrer=searchResults
Answer:
0.033
Explanation:
Please kindly check attachment for the step by step solution of the given problem.
