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aivan3 [116]
4 years ago
6

Voice authentication requires speech to text capability Facial recognition may be used for authentication The human iris is uniq

ue to an individual Fingerprints have features such as bifurcations, islands, and crossovers
A. True
B. False
Computers and Technology
1 answer:
ruslelena [56]4 years ago
3 0

Voice authentication requires speech to text capability [False]

Facial recognition may be used for authentication [True]

The human iris is unique to an individual [True]

Fingerprints have features such as bifurcations, islands, and crossovers [True]

<u>Explanation:</u>

Biometric confirmation frameworks store this biometric information so as to check a client's personality when that client gets to their record. Since this information is one of a kind to singular clients, biometric validation is commonly more secure than conventional types of multifaceted confirmation. Qualities like fingerprints, face acknowledgment, hand geometry, voice acknowledgment, palm vein acknowledgment, retina filters, iris acknowledgment, and mark check are the most well-known sorts of attributes utilized for biometric verification

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An antonym for the word “help” which may be found in a dictionary is a. Assist c. Hold b. Abandon d. None of these
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A datagram network allows routers to drop packets whenever they need to. The probability of a router discarding a packetis p. Co
tresset_1 [31]

Answer:

a.) k² - 3k + 3

b.) 1/(1 - k)²

c.) k^{2}  - 3k + 3 * \frac{1}{(1 - k)^{2} }\\\\= \frac{k^{2} - 3k + 3 }{(1-k)^{2} }

Explanation:

a.) A packet can make 1,2 or 3 hops

probability of 1 hop = k  ...(1)

probability of 2 hops = k(1-k)  ...(2)

probability of 3 hops = (1-k)²...(3)

Average number of probabilities = (1 x prob. of 1 hop) + (2 x prob. of 2 hops) + (3 x prob. of 3 hops)

                                                       = (1 × k) + (2 × k × (1 - k)) + (3 × (1-k)²)

                                                       = k + 2k - 2k² + 3(1 + k² - 2k)

∴mean number of hops                = k² - 3k + 3

b.) from (a) above, the mean number of hops when transmitting a packet is k² - 3k + 3

if k = 0 then number of hops is 3

if k = 1 then number of hops is (1 - 3 + 3) = 1

multiple transmissions can be needed if K is between 0 and 1

The probability of successful transmissions through the entire path is (1 - k)²

for one transmission, the probility of success is (1 - k)²

for two transmissions, the probility of success is 2(1 - k)²(1 - (1-k)²)

for three transmissions, the probility of success is 3(1 - k)²(1 - (1-k)²)² and so on

∴ for transmitting a single packet, it makes:

     ∞                             n-1

T = ∑ n(1 - k)²(1 - (1 - k)²)

    n-1

   = 1/(1 - k)²

c.) Mean number of required packet = ( mean number of hops when transmitting a packet × mean number of transmissions by a packet)

from (a) above, mean number of hops when transmitting a packet =  k² - 3k + 3

from (b) above, mean number of transmissions by a packet = 1/(1 - k)²

substituting: mean number of required packet =  k^{2}  - 3k + 3 * \frac{1}{(1 - k)^{2} }\\\\= \frac{k^{2} - 3k + 3 }{(1-k)^{2} }

6 0
3 years ago
What is the output?
NemiM [27]

Answer:

False

Explanation:

Put it in IDLE and got it.

4 0
3 years ago
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