The correct structure of the question is as follows:
The function f(x) = x^3 describes a cube's volume, f(x) in cubic inches, whose length, width, and height each measures x inches. If x is changing, find the (instantaneous) rate of change of the volume with respect to x at the moment when x = 3 inches.
Answer:
Step-by-step explanation:
Given that:
f(x) = x^3
Then;
V = x^3
The rate whereby V is changing with respect to time is can be determined by taking the differentiation of V
dV/dx = 3x^2
Now, at the moment when x = 3;
dV/dx = 3(3)^2
dV/dx = 3(9)
dV/dx = 27 cubic inch per inch
Suppose it is at the moment when x = 9
Then;
dV/dx = 3(9)^2
dV/dx = 3(81)
dV/dx = 243 cubic inch per inch
Sin J = cos K
sin J = cos (90 - J)
So, K = 90 - J
Therefore, 60 deg, 30 deg satisfy the condition sin J = cos K.
Answer:
pretty easy ヽ(･∀･)ﾉ
Step-by-step explanation:
When you are dividing by a decimal, you have to move the decimal to the right however many places to make it a whole number. In this case if you move the decimal 1 place to the right (that means multiplying by 10) .8 becomes 8. However many places you move the decimal, you have to do the same for the other number. In this case 30.0 becomes 300. Now the problem becomes 300 ÷ 8.
Yes there is an error in this statement.
because x^2 = 25
so x = 5...this is one condition
Another condition is x = -5
(-5)^2 = 25 (this is also true)
