This can be solve by using the formula
D = P( 1 – i)^n
Where d is the depreciation value after n years
P is the initial value
i is the depreciation rate
n is the years
D = 1/3 ( 1800)
D = 600
So
600 = 1800 ( 1- 0.45)^n
Solve for n
<span>N = 1.83 years</span>
Answer:
0.012t + 28 = 30
Step-by-step explanation:
The depth starts at 28 meters. The amount of increase in t minutes will be 0.012t, so the total depth after t minutes is ...
0.012t +28
We want to find when that is equal to 30, so the appropriate equation is ...
0.012t +28 = 30
Answer:
Step-by-step explanation:
Assuming the toppings don't have to be the same
4*10*10*10*10=4000
If the toppings have to be different:
4*10*9*8*7=20160
Answer:
3^-5
Step-by-step explanation:
x^-3=1/x^3
this rule applies to all negative exponents lol