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rosijanka [135]
1 year ago
11

Jesaria can jump rope 42 times in 20 seconds at this rate how many times can she jump rope in 2 minute

Mathematics
1 answer:
Verizon [17]1 year ago
5 0

Jesaria jump rope 42 times in 20 seconds

So in 01 second jump rate=42/20

In 01 minute (60 second)

she will jump = 42x60/20

=126 times answer

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Write an equation in point-slope form for a line passes through the point (8,-7) and has a slope of 5/4.
fomenos

Answer:

y+7=5/4(x-8)

Step-by-step explanation:

y-y1=m(x-x1)

y-(-7)=5/4(x-8)

y+7=5/4(x-8)

8 0
2 years ago
A water tank that holds 500 gallons leaks LaTeX: \frac{1}{2}1 2 gallon of water every hour. What is the rate of change for the f
Paul [167]

Answer:

250

Step-by-step explanation:

4 0
2 years ago
Consider the two data sets below:
alina1380 [7]

Answer:

<u><em>Option c) The data sets will have the same values of their interquartile range.</em></u>

<u><em></em></u>

Explanation:

<u>1. The values are in order: </u>they are in increasing oder, from lowest to highest value.

<u>2. Calculate the interquartile range.</u>

<em />

<em>Interquartile range</em>, IQR, is the third quartile, Q3, less the first quartile Q1:

  • IQR = Q3 - Q1

To find the first and the third quartile, first find the median:

<u>Data Set 1</u>: 19, 25, 35, 38, 41, 49, 50, 52, 59

             [19, 25, 35, 38],  41,  [49, 50, 52, 59]

                                         ↑

                                     median = 41

   

<u>Data Set 2</u>: 19, 25, 35, 38, 41, 49, 50, 52, 99

             [19, 25, 35, 38] , 41,  [49, 50, 52, 99]

                                         ↑

                                      median = 41

Now find the median of each subset: the values below the median and the values above the median.

Data set 1: <u>First quartile</u>

                [19, 25, 35, 38],

                            ↑

                           Q1 = [25 + 35] / 2 = 30

                   <u>Third quartile</u>

                   [49, 50, 52, 59]

                                ↑

                                Q3 = [50 + 52] / 2 = 51

                     IQR = Q3 - Q1 = 51 - 30 = 21

Data set 2: <u> First quartile</u>

                   [19, 25, 35, 38]

                               ↑

                               Q1 = [25 + 35] / 2= 30

                  <u>Third quartile</u>

                   [49, 50, 52, 99]

                                ↑

                                Q3 = [52 + 50]/2 = 51

                   IQR = 51 - 30 = 21

Thus, it is shown that the data sets have will have the same values for the interquartile range: IQR = 21. (option c)

This happens because replacing one extreme value (in this case the maximum value) by other extreme value does not affect the median.

<em>An outlier will change the range</em> because the range is the maximum value less the minimum value.

5 0
2 years ago
Please help me on this will give you brainliest
goblinko [34]
The answer is 4=97 1=83 3=83
Hope this helps if it does please consider making my answer brainliest
8 0
3 years ago
57 divided by 8 with remainder.
zavuch27 [327]
If you would like to calculate 57 divided by 8, you can do this using the following steps:

57 divided by 8:
57 / 8 = 7 1/8 = 7.125

The correct result would be 7 1/8 or 7.125.
8 0
3 years ago
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