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Tpy6a [65]
3 years ago
10

Carol makes 9 1/3 cups of snack mix.She puts 2/3 all the snack mix into plastic bags. She puts of a cup of the snack mix in each

bag. How many plastic bags does Carol need
Mathematics
1 answer:
m_a_m_a [10]3 years ago
5 0

Carol has 6 2/9 cups of snack mix to put into plastic bags, so she would need 6 plastic bags and she would have 2/9 of snack mix left over.



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Find the two smallest possible solutions to part 1a​
bixtya [17]
<h3>Answer: A. 5/12, 25/12</h3>

============================

Work Shown:

12*sin(2pi/5*x)+10 = 16

12*sin(2pi/5*x) = 16-10

12*sin(2pi/5*x) = 6

sin(2pi/5*x) = 6/12

sin(2pi/5*x) = 0.5

2pi/5*x = arcsin(0.5)

2pi/5*x = pi/6+2pi*n or 2pi/5*x = 5pi/6+2pi*n

2/5*x = 1/6+2*n or 2/5*x = 5/6+2*n

x = (5/2)*(1/6+2*n) or x = (5/2)*(5/6+2*n)

x = 5/12+5n or x = 25/12+5n

these equations form the set of all solutions. The n is any integer.

--------

The two smallest positive solutions occur when n = 0, so,

x = 5/12+5n or x = 25/12+5n

x = 5/12+5*0 or x = 25/12+5*0

x = 5/12 or x = 25/12

--------

Plugging either x value into the expression 12*sin(2pi/5*x)+10 should yield 16, which would confirm the two answers.

7 0
3 years ago
Read 2 more answers
Suppose after 2500 years an initial amount of 1000 grams of a radioactive substance has decayed to 75 grams. What is the half-li
krok68 [10]

Answer:

The correct answer is:

Between 600 and 700 years (B)

Step-by-step explanation:

At a constant decay rate, the half-life of a radioactive substance is the time taken for the substance to decay to half of its original mass. The formula for radioactive exponential decay is given by:

A(t) = A_0 e^{(kt)}\\where:\\A(t) = Amount\ left\ at\ time\ (t) = 75\ grams\\A_0 = initial\ amount = 1000\ grams\\k = decay\ constant\\t = time\ of\ decay = 2500\ years

First, let us calculate the decay constant (k)

75 = 1000 e^{(k2500)}\\dividing\ both\ sides\ by\ 1000\\0.075 = e^{(2500k)}\\taking\ natural\ logarithm\ of\ both\ sides\\In 0.075 = In (e^{2500k})\\In 0.075 = 2500k\\k = \frac{In0.075}{2500}\\ k = \frac{-2.5903}{2500} \\k = - 0.001036

Next, let us calculate the half-life as follows:

\frac{1}{2} A_0 = A_0 e^{(-0.001036t)}\\Dividing\ both\ sides\ by\ A_0\\ \frac{1}{2} = e^{-0.001036t}\\taking\ natural\ logarithm\ of\ both\ sides\\In(0.5) = In (e^{-0.001036t})\\-0.6931 = -0.001036t\\t = \frac{-0.6931}{-0.001036} \\t = 669.02 years\\\therefore t\frac{1}{2}  \approx 669\ years

Therefore the half-life is between 600 and 700 years

5 0
3 years ago
Help plss !! Will give branliest to who ever has the best answer
ozzi

Answer:

a c and e hope it helps :D

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Ms. Thomas is saving up to buy a new phone. She has already saved $200 and adding $50 per month to her saving account. She wants
melomori [17]

Answer:

Step-by-step explanation:

The inequality equation can be determined by using the concept of arithmetic progression;

a(n) = a₁ + (n-1)d

where;

a(n) = 1000

a = 200

d = 50

The inequality will be:

1000 = 200 + ( n - 1) 50

1000 = 200 + 50n - 50

1000 = 150 + 50 n

1000 - 150 = 50 n

850 = 50 n

n = 850/50

n = 17 months

So, if Ms. Thomas is planning to have more than $1000 in her account, she will need to save for 17 moths before she can buy the phone.

5 0
2 years ago
How do we best help him learn his Multiplication table ….help for 3rd grade grandson
laiz [17]

Answer:

you can get flash cards and work with him everyday that's how I got mine

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3 years ago
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