Answer:
Case 1: The purchasing power of money will decrease, prices will increase and nominal interest rate will decrease.
Case 2: The purchasing power of money will increase, prices will decrease and nominal interest rate will increase.
Case 3: The purchasing power of money will increase, prices will decrease and nominal interest rate will increase.
Case 4: The purchasing power of money will decrease, prices will increase and nominal interest rate will decrease.
Explanation:
Case 1: The purchasing power of money will decrease, prices will increase and nominal interest rate will decrease.
Case 2: The purchasing power of money will increase, prices will decrease and nominal interest rate will increase.
Case 3: The purchasing power of money will increase, prices will decrease and nominal interest rate will increase.
Case 4: The purchasing power of money will decrease, prices will increase and nominal interest rate will decrease.
Answer:
The electrical action has the better expected monetary value with 492,000
Explanation:
We will multiply the expected outcome by their probability then, we add them to get the expected monetary value per option:
![\left[\begin{array}{ccccc}$WIND-UP&$Return&$Probability&$Weight\\$Light&325000&0.1&32500\\$Morerate&190000&0.3&57000\\$Heavy&170000&0.6&102000\\$Total&&1&191500\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccccc%7D%24WIND-UP%26%24Return%26%24Probability%26%24Weight%5C%5C%24Light%26325000%260.1%2632500%5C%5C%24Morerate%26190000%260.3%2657000%5C%5C%24Heavy%26170000%260.6%26102000%5C%5C%24Total%26%261%26191500%5C%5C%5Cend%7Barray%7D%5Cright%5D)
![\left[\begin{array}{cccc}$PNEUMATIC&Return&Probability&Weight\\$Light&300000&0.1&30000\\$Morerate&420000&0.3&126000\\$Heavy&400000&0.6&240000\\$Total&&1&396000\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D%24PNEUMATIC%26Return%26Probability%26Weight%5C%5C%24Light%26300000%260.1%2630000%5C%5C%24Morerate%26420000%260.3%26126000%5C%5C%24Heavy%26400000%260.6%26240000%5C%5C%24Total%26%261%26396000%5C%5C%5Cend%7Barray%7D%5Cright%5D)
![\left[\begin{array}{cccc}$Electrical&Return&Probability&Weight\\$Light&-600000&0.1&-60000\\$Morerate&240000&0.3&72000\\$Heavy&800000&0.6&480000\\$Total&&1&492000\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D%24Electrical%26Return%26Probability%26Weight%5C%5C%24Light%26-600000%260.1%26-60000%5C%5C%24Morerate%26240000%260.3%2672000%5C%5C%24Heavy%26800000%260.6%26480000%5C%5C%24Total%26%261%26492000%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Traditionally, the formulas used to express a firm's cost of equity are the dividend capitalization model and the capital asset pricing model (CAPM).
Explanation:
Generally, two risk components determine a firm's cost of equity. The first is the systematic risk associated with the broader equity market. All firms are exposed to this risk, and it cannot be mitigated through diversification.
The second risk component is the unsystematic risk associated with the firm in question. This risk, often reflected as beta, a measure of the stock's volatility in relation to the volatility of the broader market, can be mitigated via diversification.
Frequently lacks effective communication channels across departments. Communication between departments can be an issue in this structure.
Answer:
Job 301 $ 11,000
Job 302 $ 16,500
Job 303 $ 22,000
Explanation:

To calculate the overhead rate <u>we divide the estimated overhead cost by the estimated cost driver:</u>

0.55 overhead rate
Job 301 $20,000 labor cost x 0.55 overhead rate
11,000
Job 302 $30,000 labor cost x 0.55 overhead rate
16,500
Job 303 $40,000 labor cost x 0.55 overhead rate
22,000