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3 years ago

Easy points !! HELP PLEASE

Mathematics

2 answers:

rjkz [21]3 years ago

7 0

Answer:

I cant see the picture...

Step-by-step explanation:

AnnyKZ [126]3 years ago

3 0

Answer:

2 and 3

Step-by-step explanation:

The pair of angles that is complementary are:

2 and 3

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Can anyone help solve this for me ASAP. Thanks!

Anuta_ua [19.1K]

Answer:

x = 20

y = 26

Step-by-step explanation:

40 and 2x are vertical angles, so they're equal to each other.

40 = 2x

Divide both sides by 2

x = 20

We see that 40 and 5y + 10 are a linear pair, which means they add up to 180.

5y + 10 + 40 = 180

5y + 50 = 180

5y = 130

y = 26

8 0

2 years ago

For the function F (X) = (x - 2)^2 + 4, identify the vertex.

VLD [36.1K]

Answer:

The answer will be D. (2,4)

5 0

2 years ago

COMO SE SACA UNA TABLA DE FRECUENCIA?????=? URGENTE ES PA HOY

xz_007 [3.2K]

Answer:

Para construir una tabla de frecuencias, procedemos de la siguiente manera:

Construye una tabla con tres columnas. La primera columna muestra lo que se organiza en orden ascendente (es decir, las marcas). ...

Repase la lista de marcas. ...

Cuente el número de marcas de conteo para cada marca y escríbalo en la tercera columna.

8 0

2 years ago

Simplify the following expression 4/1/4-5/2

lorasvet [3.4K]

Answer:

$1\frac{3}{4}$

Step-by-step explanation:

$4 \frac{1}{4} - \frac{5}{2}$ = $1 \frac{3}{4}$

5 0

2 years ago

The length of a rectangle is 5 metres less than twice the breadth. If the perimeter is 50 meters,find the length and breadth

MAXImum [283]

As per the given question, it is stated that the length of a rectangle is 5 m less than twice the breadth.

Assumption : Let us assume the length as "l" and width as "b". So,

$\twoheadrightarrow \quad\sf{ Length =2(Width)-5}$

$\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}$

Also, we are given that the perimeter of the rectangle is 50 m. Basically, we need to apply here the formula of perimeter of rectangle which will act as a linear equation here.

$\\ \twoheadrightarrow \quad\sf{ Perimeter_{(Rectangle)} = 2(\ell +b) } \\$

l denotes length
b denotes breadth

$\\ \twoheadrightarrow \quad\sf{50= 2(2b-5+b)} \\$

$\\ \twoheadrightarrow \quad\sf{50= 2(3b-5)} \\$

$\\ \twoheadrightarrow \quad\sf{50= 6b - 10} \\$

$\\ \twoheadrightarrow \quad\sf{50+10= 6b} \\$

$\\ \twoheadrightarrow \quad\sf{60= 6b} \\$

$\\ \twoheadrightarrow \quad\sf{\cancel{\dfrac{60}{6}}=b} \\$

$\\ \twoheadrightarrow \quad\underline{\bf{10\; m = Width }} \\$

Now, finding the length. According to the question,

$\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}$

$\twoheadrightarrow \quad\sf{ \ell=2(10)-5\; m}$

$\twoheadrightarrow \quad\sf{ \ell=20-5\; m}$

$\\ \twoheadrightarrow \quad\underline{\bf{15\; m = Length }} \\$

Therefore, length and breadth of the rectangle is 15 m and 10 m. 

7 0

3 years ago