Let i = sqrt(-1) which is the conventional notation to set up an imaginary number
The idea is to break up the radicand, aka stuff under the square root, to simplify
sqrt(-8) = sqrt(-1*4*2)
sqrt(-8) = sqrt(-1)*sqrt(4)*sqrt(2)
sqrt(-8) = i*2*sqrt(2)
sqrt(-8) = 2i*sqrt(2)
<h3>Answer is choice A</h3>
Answer:
8.33333333333
Step-by-step explanation:
Solution for 3x-7=18 equation:
3x - 7 = 18
3x = 18 + 7
3x = 25 (divide both sides by 3 to get x)
3x/3 = 25/3
x = 8.33333333333
Factor out the cos<span>θ:
</span>cosθ (2sin<span>θ + sqrt3) = 0
</span>Therefore, the only ways this can happen are if either cosθ = 0 or if (2sin<span>θ + sqrt3) = 0
</span>The first case, cosθ = 0 only at θ <span>= pi/2, 3pi/2.
</span>The second case, <span>(2sin<span>θ + sqrt3) = 0 simplifies to:
</span></span>sin<span>θ = (-sqrt3)/2
</span><span><span>θ = 4pi/3, 5pi/3
</span></span><span><span>Therefore the answer is A.
</span></span>
The absolute value of -72 is 72.
Absolute value is essentially just making the number given positive.
If the given number is already positive then the absolute value is the same as the original number
Hope this helped!
~Just a girl in love with Shawn Mendes
When it tells you to find h(2), that means you plug in 2 for x.
If 2x^3 (to the third power)
2(2)^3-3
1. PEMDAS, exponents first
2^3=8
2. multiply
8x2=16
3. subtract
16-3=13
Hope this helps!
