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Shkiper50 [21]
3 years ago
11

3(s-5)/4 -3 = 4s- (s-3)/2pls answer fast​

Mathematics
1 answer:
Jobisdone [24]3 years ago
5 0

Answer:

s =  \frac{9± \sqrt{ - 39} }{4}

Step-by-step explanation:

\frac{3(s - 5)}{4 - 3}  =  \frac{4s \times (s - 3)}{2}

➡️ \frac{3(s - 5)}{1}  = 2s \times (s - 3)

➡️ 3s - 15 = 2 {s}^{2}  - 6s

➡️ 3s - 15  -  2 {s}^{2}  + 6s = 0

➡️ 9s - 15 - 2 {s}^{2}  = 0

➡️ - 2 {s}^{2}  + 9s - 15 = 0

➡️ 2 {s}^{2}  - 9s + 15 = 0

➡️ s =  \frac{ - ( - 9)± \sqrt{( - 9 {)}^{2}  - 4 \times 2 \times 15} }{2 \times 2}

➡️ s =  \frac{9± \sqrt{81 - 120} }{4}

➡️ s =  \frac{9± \sqrt{ - 39} }{4}

➡️ s∉ℝ

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<h3>What does it means that x is a root of a function f(x)?</h3>


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