Need help writing a quadratic equation from a function given the graph, screenshot posted of the question

Mathematics

1 answer:

Maslowich3 years ago

6 0

Hello from MrBillDoesMath!

Answer: g(x) = (x+3) ^2 + 3

Discussion:

First, the graph looks like the parabola y = x^2 BUT its smallest y-value is +3. That suggests the equation g(x) = x^2 + 3 BUT the parabola is shifted 3 units to the left. This suggest we take our last guess (x^2 +3) and shift it 3 units to the left, giving g(x) = (x+3)^2 + 3

Note that g(-3) = (-3 +3)^2 + 3 = 3

Regards, MrB

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IRISSAK [1]

Answer: option c or 3 because you gotta take out the 6 so u do -6 which left is negative and right is positive and then get rid of the +2 exponent so up is positive and down is negative so you move -2 which is down.

Step-by-step explanation:

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3 years ago

Select the correct answer. This graph represents a quadratic function. What is the value of a in this function’s equation? A)-1

Schach [20]

Answer:

Step-by-step explanation:

We will use the work form of a quadratic to determine what a is...in fact we will write the equation for the whole thing in the process, because it's part of solving for a.

y = ±|a|(x - h)² + k

where x and y are from a coordinate point on the graph, h and k are the coordinates of the vertex, the absolute value of a indicates how steep or flat the graph is compared to the parent graph, and the ± is because a positive parabola opens up and a negative one opens upside down.

The vertex is (0, 9) and the coordinate point I chose to use is (3, 0). Filling those in and solving for a:

0 = ±|a|(3 - 0)² + 9 and

0 = ±|a|(3)² + 9 and

-9 = ±|a|9 and

-1 = ±|a| so a = 1. Because this is an upside down parabola the negative is out front, but a is independent of it. The correct choice is C. The quadratic function is

$y=-x^2+9$ or in more detailed form: