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3 years ago

A number increased by 10

Mathematics

2 answers:

Natasha_Volkova [10]3 years ago

7 0

Answer:

Step-by-step explanation:

just got it right on plato

ra1l [238]3 years ago

7 0

Answer:

im pretty sure we need the previous value

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Given g(x)=8x+3 find the following g(-1) and g(2a+1)

Degger [83]

Answer:

g(-1) = -5

g(2a+1) = 16a+11

Step-by-step explanation:

Substitute the given value into the function and evaluate.

So for g(x) = 8x+3

You substitute g(-1)

So g(-1) = 8(-1)+3

That is how you get -5

Then g(2a+1)

So g(2a+1) = 8(2a+1)+3

Thats how you get 16a+11

Hope this helps. Mark as brainlist

4 0

2 years ago

Amber, Bernie, and Carlos are working on a problem together. Their goal is to correctly apply the difference of cubes formula to

NeX [460]

Answer: Carlos is correct

Step-by-step explanation:

2x^5-250x^2

The first step is to factorize out 2x^2

2x^2(x^3-125)

This can be rewritten as

2x^2(x^3-5^3),

Recall, difference if cube (a^3-b^3)

= (a-b)(a^2 +ab + b^2)

from our equation,

a= x

b = 5.

So the difference of cubes will be

2x^2[(x-5) (x^2 + 5x + 5^2)]

=2x^2[(x-5) (x^2 + 5x + 25)]

Carlos followed these steps. So he is correct. Carlos is correct because he correctly factored the GCF, identified a and b, and applied the difference of cubes method.

Amber is incorrect because 125 is equal to b3, not b.

Bernie is incorrect because x2 is not the GCF of the polynomial. The GCF is 2x^2.

6 0

3 years ago

For each vector field f⃗ (x,y,z), compute the curl of f⃗ and, if possible, find a function f(x,y,z) so that f⃗ =∇f. if no such f

butalik [34]

$\vec f(x,y,z)=(2yze^{2xyz}+4z^2\cos(xz^2))\,\vec\imath+2xze^{2xyz}\,\vec\jmath+(2xye^{2xyz}+8xz\cos(xz^2))\,\vec k$

Let

$\vec f=f_1\,\vec\imath+f_2\,\vec\jmath+f_3\,\vec k$

The curl is

$\nabla\cdot\vec f=(\partial_x\,\vec\imath+\partial_y\,\vec\jmath+\partial_z\,\vec k)\times(f_1\,\vec\imath+f_2\,\vec\jmath+f_3\,\vec k)$

where $\partial_\xi$ denotes the partial derivative operator with respect to $\xi$ . Recall that

$\vec\imath\times\vec\jmath=\vec k$

$\vec\jmath\times\vec k=\vec i$

$\vec k\times\vec\imath=\vec\jmath$

and that for any two vectors $\vec a$ and $\vec b$ , $\vec a\times\vec b=-\vec b\times\vec a$ , and $\vec a\times\vec a=\vec0$ .

The cross product reduces to

$\nabla\times\vec f=(\partial_yf_3-\partial_zf_2)\,\vec\imath+(\partial_xf_3-\partial_zf_1)\,\vec\jmath+(\partial_xf_2-\partial_yf_1)\,\vec k$

When you compute the partial derivatives, you'll find that all the components reduce to 0 and

$\nabla\times\vec f=\vec0$

which means $\vec f$ is indeed conservative and we can find $f$ .

Integrate both sides of

$\dfrac{\partial f}{\partial y}=2xze^{2xyz}$

with respect to $y$ and

$\implies f(x,y,z)=e^{2xyz}+g(x,z)$

Differentiate both sides with respect to $x$ and

$\dfrac{\partial f}{\partial x}=\dfrac{\partial(e^{2xyz})}{\partial x}+\dfrac{\partial g}{\partial x}$

$2yze^{2xyz}+4z^2\cos(xz^2)=2yze^{2xyz}+\dfrac{\partial g}{\partial x}$

$4z^2\cos(xz^2)=\dfrac{\partial g}{\partial x}$

$\implies g(x,z)=4\sin(xz^2)+h(z)$

Now

$f(x,y,z)=e^{2xyz}+4\sin(xz^2)+h(z)$

and differentiating with respect to $z$ gives

$\dfrac{\partial f}{\partial z}=\dfrac{\partial(e^{2xyz}+4\sin(xz^2))}{\partial z}+\dfrac{\mathrm dh}{\mathrm dz}$

$2xye^{2xyz}+8xz\cos(xz^2)=2xye^{2xyz}+8xz\cos(xz^2)+\dfrac{\mathrm dh}{\mathrm dz}$

$\dfrac{\mathrm dh}{\mathrm dz}=0$

$\implies h(z)=C$

for some constant $C$ . So

$f(x,y,z)=e^{2xyz}+4\sin(xz^2)+C$

3 0

3 years ago

A triangle in the coordinate plane has coordinates of (3, 5), (1, −3), and (−3, 4). It is translated so that its new coordinates

Alisiya [41]

Given that a triangle in the coordinate plane has coordinates of (3, 5), (1, −3), and (−3, 4). Now these points are translated and the new coordinates are (1, 7), (−1, −1), and (−5, 6).

Questioon says to find which type of translation occured from the given choices.

It can be easily found by drawing the given coordinates.

Original position of the triangle is drawn in Brwon colour.

New position of the triangle is drawn in Green colour.

From graph we can clearly see that each of the original coordinate moves two unit left then 2 units upward to get new coordinate.

Hence choice "A) It moved left two units and up two units." is the final answer.

4 0

3 years ago

Read 2 more answers

Evaluate this expression for a = 3 and b = 4.

ahrayia [7]

Answer:

Step-by-step explanation:

a = 3

b = 4

$b(a + 4)-3(3 + 2)+3 - 2\\a = 3,b=4\\4(3+4)-3(5)+3 - 2\\4(7)-15+3 - 2\\28-14\\\\14$

8 0

3 years ago