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choli [55]
3 years ago
10

A number increased by 10

Mathematics
2 answers:
Natasha_Volkova [10]3 years ago
7 0

Answer:

20

Step-by-step explanation:

just got it right on plato

ra1l [238]3 years ago
7 0

Answer:

im pretty sure we need the previous value

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Simplify: -6(-8) + 15 =
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Step-by-step explanation:

63

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Will measured the diameter of a penny as 1.9 cm using the ruler. What is the margin of error? 1.5 cm to 2.0 cm 1.5 cm to 2.5 cm
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The answer is 1.5cm to 2.0cm

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Ciana wants to buy a shirt that regularly cost 30$.It is on sale for 40$ off. How much is Ciana saving on the shirt?Please help
DerKrebs [107]

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I think you meant 40% off. If so...

Step-by-step explanation:

First, you have to turn 40 into a decimal - .40.

Then you multiply 30*.40 and get 12.

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Jan had x color pencils in her box and shares them equally with her friend,Talia.Her brother gives her 2 more color pencils.Jan
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A recent broadcast of a television show had a 10 ​share, meaning that among 6000 monitored households with TV sets in​ use, 10​%
Kisachek [45]

Answer:

Null and alternative hypothesis

H_0: \pi \geq0.25\\\\H_1: \pi

Test statistic z=-26.82

P-value P=0

The null hypothesis is rejected.

It is concluded that the proportion of households tuned into the program is less than 25%. The claim of the advertiser is rigth and got statistical support.

Step-by-step explanation:

We have to perform a hypothesis test of a proportion.

The claim is that less than 25% were tuned into the program, so we will state this null and alternative hypothesis:

H_0: \pi \geq0.25\\\\H_1: \pi

The signifiance level is 0.01.

The sample has a proportion p=0.1 and sample size of n=6000.

The standard deviation of the proportion, needed to calculate the test statistic, is:

\sigma_p=\sqrt{\frac{\pi(1-\pi)}{N} } =\sqrt{\frac{0.25(1-25)}{6000} } =0.0056

The test statistic is calculated as:

z=\frac{p-\pi+0.5/N}{\sigma_p} =\frac{0.1-0.25+0.5/6000}{0.0056}=\frac{-0.1499}{0.0056}  =-26.82

As this is a one-tailed test, the P-value is P(z<-26.82)=0. The P-value is smaller than the significance level (0.01), so the effect is significant.

Since the effect is significant, the null hypothesis is rejected. It is concluded that the proportion of households tuned into the program is less than 25%. The claim of the advertiser is rigth and got statistical support.

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