Answer:
a) P ( 3 ≤X≤ 5 ) = 0.02619
b) E(X) = 1
Step-by-step explanation:
Given:
- The CDF of a random variable X = { 0 , 1 , 2 , 3 , .... } is given as:
Find:
a.Calculate the probability that 3 ≤X≤ 5
b) Find the expected value of X, E(X), using the fact that. (Hint: You will have to evaluate an infinite sum, but that will be easy to do if you notice that
Solution:
- The CDF gives the probability of (X < x) for any value of x. So to compute the P ( 3 ≤X≤ 5 ) we will set the limits.

- The Expected Value can be determined by sum to infinity of CDF:
E(X) = Σ ( 1 - F(X) )

E(X) = Limit n->∞ [1 - 1 / ( n + 2 ) ]
E(X) = 1
Answer:
The residents of a city voted on whether to raise property taxes. The ratio of yes votes to no votes was 4 to 7 . If there were 10,725 total votes .
Step-by-step explanation:
Please find attached photograph for your answer.
So you need help with creating the table ?
The area of the triangle is
a=( m x n) /2 in cm² , implies 2xa = m xn
the area of the rectanglle
A= n x m in cm²
but we know <span> 2xa = m xn = A, </span>
that means the surface of the rectangle is 2 times of the area of the triangle