Answer:
- Lena's Method: 280
- Jackson's Method: 280
Step-by-step explanation:
Lena's Method:
- 8 + 12 = 20
- Plug 20 in: 14(20)
- 14(20) = 14 × 20 = 280
Jackson's Method:
- 14 × 8 = 112
- 14 × 12 = 168
- Re-write the expression: 112 + 168
- 112 + 168 = 280
I hope this helps!
345 i love your mom and I love your hair
Answer:
∑ (n = 1 to 5) (2·(-4)^(n - 1))
S5 = 2·((-4)^5 - 1)/((-4) - 1) = 410
The normal vectors to the two planes are (3, 3, 2) and (2, -3, 2). The cross product of these will be the direction vector of the line of intersection, (12, -2, -15).
Using x=0, we can find a point on this line by solving the simultaneous equations that remain:
... 3y +2z = -2
... -3y +2z = 2
Adding these, we get
... 4z = 0
... z = 0
so the point we're looking for is (x, y, z) = (0, -2/3, 0). This gives rise to the parametric equations ...
- x = 12t
- y = -2/3 -2t
- z = -15t
By letting t=2/3, we can find a point on the line that has integer coefficients. That will be (x, y, z) = (8, -2, -10).
Then our parametric equations can be written as
- x = 8 +12t
- y = -2 -2t
- z = -10 -15t
49c^2 - 25d^6
(7c)^2 - (5d^3)^2
(7c + 5d^3)(7c - 5d^3)
The answer is: (7c + 5d^3)(7c - 5d^3).
