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dem82 [27]
3 years ago
15

which expression is equivalent to 5(2x - 7) A. 2x - 35 B. 7x - 2 C. 7x - 12 D. 10x - 7 or E. 10x - 35

Mathematics
1 answer:
seraphim [82]3 years ago
4 0
<span>5(2x - 7)
= 10x - 35

answer
</span><span>E. 10x - 35</span>
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3 years ago
20 POINTS HURRY PLEASE (GIVING BRAINLIEST)
Debora [2.8K]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
What is the average rate of change for the table and graph below over the interval [0,3]?
Leokris [45]

Answer:

-2

Step-by-step explanation:

The average rate of change is the slope using the points (0, 10) and (3, 4).  The slope is found using the formula \frac{y2-y1}{x2-x1}

\frac{4-10}{3-0}= \frac{-6}{3}=-2

6 0
3 years ago
I don’t really understand?
aksik [14]

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3 0
3 years ago
A tunnel is built in form of a parabola. The width at the base of tunnel is 7 m. On
anastassius [24]

Given:

The width at the base of parabolic tunnel is 7 m.

The ceiling 3 m from each end of the base there are light fixtures.

The height to light fixtures is 4 m.

To find:

Whether it is possible a trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel.

Solution:

The width at the base of tunnel is 7 m.

Let the graph of the parabola intersect the x-axis at x=0 and x=7. It means x and (x-7) are the factors of the height function.

The function of height is:

h(x)=ax(x-7)             ...(i)

Where, a is a constant.

The ceiling 3 m from each end of the base there are light fixtures and the height to light fixtures is 4 m. It means the graph of height function passes through the point (3,4).

Putting x=3 and h(x)=4 in (i), we get

4=a(3)((3)-7)

4=a(3)(-4)

\dfrac{4}{(3)(-4)}=a

-\dfrac{1}{3}=a

Putting a=-\dfrac{1}{3}, we get

h(x)=-\dfrac{1}{3}x(x-7)              ...(ii)

The center of the parabola is the midpoint of 0 and 7, i.e., 3.

The width of the truck is 4 m. If is passes through the center then the truck must m 2 m on the left side of the center and 2 m on the right side of the center.

2 m on the left side of the center is x=1.5.

A trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel is possible if h(1.5) is greater than 2.8.

Putting x=1.5 in (ii), we get

h(1.5)=-\dfrac{1}{3}(1.5)(1.5-7)

h(1.5)=-(0.5)(-5.5)

h(1.5)=2.75

It is clear that h(1.5)<2.8, therefore the trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel is not possible.

4 0
3 years ago
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