Answer:
The solution to the inequality is all real values of n that respect the following condition: 2 < n < 6
Step-by-step explanation:
First, we need to separate the modulus from the rest of equation. So
3-l4-nl>1
-|4-n|>1-3
-|4-n|>-2
Multiplying everything by -1.
|4-n|<2
How to solve:
|x| < a means that -a<x<a
In this question:
|4-n|<2
-2<4-n<2
This means that:
4 - n > -2
-n > -6
Multiplying by -1
n < 6
And
4 - n < 2
-n < -2
Multiplying by 1
n > 2
Intersection:
Between n > 2 and n < 6 is 2 < n < 6
So the solution to the inequality is all real values of n that respect the following condition: 2 < n < 6
Answer:
b - 9 = 2 I believe would be it
Answer:
dy/dx = (x^2 - 3)^sin x [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)]
Step-by-step explanation:
y = (x^2 - 3)^sinx
ln y = ln (x^2 - 3)^sinx
ln y = sin x * ln (x^2 - 3)
1/y * dy/dx = sin x * {1 / (x^2 - 3)} * 2x + ln(x^2 - 3) * cos x
1/y dy/dx = 2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)
dy/dx = [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)] * y
dy/dx = (x^2 - 3)^sin x [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)]
Answer:
T(3) = 13
Step-by-step explanation:
If we are trying to find the 3rd term of this <em>specific </em>sequence, then we simply plug in 3 as n.
T(3) = (3)² + 4
T(3) = 9 + 4
T(3) = 13
However, this isn't proper notation for an arithmetic or geometric sequence.
Answer:
An irrational number is a number that has no pattern and has no end. For example 3 divided by 7 is an irrational number because of the lack of pattern and never-ending decimal.
