Ask question

Ask question

All categories

3 years ago

6

A bus traveled 336 miles in 7 hours.It traveled the same number of miles each hour.If the bus continues at the same number of mi

les per hour how many miles will the bus driver travel in 15 hours? Explain

1 answer:

Leno4ka [110]3 years ago

7 0

Answer:

kl;jjo;s njj

Step-by-step explanation:

You might be interested in

Simplify 9 + 6k +3 +212 +3 +7

melisa1 [442]

Answer:

6k+234

Step-by-Step Explanation:

Add 9, 3, 212, 3, and 7. You get 234. You can't change 6k because the variable, so you end up with 6k+234.

8 0

2 years ago

Read 2 more answers

a triangle has two angles that measure 47° and 67° what is the measure of the third angle in this triangle

Anna007 [38]

The answer to your math question is 66°.
Adding 47° and 67° is 114°.
Subtracting 114° from 180° equals 66°.

4 0

3 years ago

What is the slope of (2,8) and (1,-3)

icang [17]

Answer:

Step-by-step explanation:

m= y2 - y1/x2 - x1

m= -3 - 8 /1 - 2

m=-11/-1

m=11

8 0

2 years ago

Read 2 more answers

A bookshelf sits on top of a large desk. Together, their height is 6.75 feet. The difference between their heights is 1.85 feet.

slavikrds [6]

Answer: 4.9

Step-by-step explanation:

8 0

2 years ago

Please help with the questions in the image

iren2701 [21]

Step-by-step explanation:

This seems to be calculus 1.

<u>Question a</u>

We have $-2x^3 + 5x^2 + 9$

m = slope = derivative

Find the derivative / slope of $-2x^3 + 5x^2 + 9$

We do this by differentiating the polynomials. There are a few methods to do this but I am going to use the power rule, which we multiply the constant by the exponent on the variable and subtract one from the exponent.

$\frac{d}{dx}(-2x^3 + 5x^2 + 9)$

$-6x^2 + 10x$

$m = -6x^2 + 10x$ when x = a

<em>Now that we have this information, we can answer question b</em>

<u>Question b</u>

<u>The tangent line for Point (1, 12)</u>

First find the slope by using our derivative.

$m = -6x^2 + 10x$

$m = -6(1)^2 + 10(1)$

$m = -6 + 10x$

$m = 4$

Now that we have our slope, use point slope form to find our tangent line

$y - 12 = 4(x - 1)$

$y(x) = 4x + 8$

<u>Now lets do the same for the Point (2, 13)</u>

Find the slope at the point.

$m = -6x^2 + 10x$

$m = -6(2)^2 + 10(2)$

$m = -24 + 10$

$m = -4$

Now find the tangent line using point slope form of a line.

$y(x) - 13 = -4(x - 2)$

$y(x) = -4x + 21$

Now graph the lines, which I have done and you can see by viewing the image I have attached.

6 0

3 years ago