"y>-2x+2 and y>-2x+5" are illustrated graphically by 2 straight dashed lines with slope -2. The lines are parallel because their slopes (-2) are the same. One line has y intercept 2 and the other has y intercept 5. The latter is above the former. Since both inequality signs are " > " we must shade the area ABOVE each of the 2 lines. The solution set is the area of the graph that has been shaded twice, once for y>-2x+2 and again for y>-2x+5. It's y>-2x+5 that has been shaded twice; this area is immediately above the line y>-2x+5.
Answer:
its 3.05
Step-by-step explanation:
M<ABC = m<EBD = 36 (vertical angles)
78 - x + 36 + 3x - 10 = 180 (straight angle)
Now solve for x
78 - x + 36 + 3x - 10 = 180
2x + 68 = 180
- 68 -68 (subtract 68 on both sides)
2x = 58
x = 29
The simplified form is C .
