William has $12.80 in coins to be deposited in the bank. There are 3 times as many quarters as nickels and 20 more dimes than ni
1 answer:
Let the number of nickels be = n
Let the number of dimes be = d
Let the number of quarter be = q
Total money William has = $12.80
As given, there are 3 times as many quarters as nickels
And 20 more dimes than nickels
As total money is $12.80
Putting the values of 'q' and 'd' to find 'n'
Hence the number of nickels are = 12
If you want to also find dime and quarter, then
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Answer:
n is a positive integer and here 90, 91, 92, 93, 94 and 95 is 9⁰ = 1
9¹ = 9
9² = 81
9³ = 729
9⁴ = 6561
9⁵ = 59049
so mathematical induction is prove given below.
Step-by-step explanation:
9⁰ = 1
9¹ = 9
9² = 81
9³ = 729
9⁴ = 6561
9⁵ = 59049
lets us consider by P (n) for the base case n = 0 then 9⁰ = 1 So P (1) is true
k ≥ 1so consider all integers
1≤l≤ k
There is a need to prove P (k+1)
if k is odd
=
.9.
is 9 so
= 9 +10m
then
= 9 ( 9 + 10m)
=81 + 10 (9m)
so digit is 1 and k +1 is even
Answer:
Critical value: z = 1.28
The 80% confidence interval for the mean repair cost for the washers is between $46.487 and $82.033.
Step-by-step explanation:
We have that to find our level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of
So it is z with a pvalue of 1-0.1 = 0.9, so z = 1.28
Now, find the margin of error M as such
In which is the standard deviation of the population and n is the size of the sample.
So
The lower end of the interval is the mean subtracted by M. So 64.26 - 17.773 = $46.487.
The upper end of the interval is M added to the mean. So 64.26 + 17.773 = $82.033.
The 80% confidence interval for the mean repair cost for the washers is between $46.487 and $82.033.