Answer: Apply Hardy-Weinberg Equilibrium equation
Explanation:
Assuming the known parameters are the
frequency of two alleles 'B'and 'b' in a certain plant species, where 'B' is 0.19 and 'b' is 0.81
To calculate the percentage of heterozygous individuals in the population.
Apply Hardy-Weinberg Equilibrium equation, where heterozygotes are represented by the 2pq term.
Therefore, the number of heterozygous individuals (Bb) is equal to 2pq
2 × 0.19 × 0.81 = 0.31 or 31%
(b) To calculate the percentage of homozygous recessives in the population.
The homozygous recessive individuals (bb) are represented by the q^2 term in the H-W equilibrium
0.81 × 0.81 = 0.66 or 66%
