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faust18 [17]
3 years ago
6

What must be true about the discriminant of this quadratic equation for the mentioned values of k? Assume p>0.

Mathematics
1 answer:
Goryan [66]3 years ago
4 0
<span>1/(4p)(x-h)^2+k=0

</span><span>1/(4p)(x-h)^2 = -k
</span>
<span>k(4p)(x-h)^2+1=0

4kp (x^2 - 2xh + h^2) + 1 = 0

4kp x^2 - 8kph x + 4kph^2+1 = 0

D = (-8kph)^2 - 4(4kp)(4kph^2+1) = 64(kph)^2 - 64(kph)^2 - 16kp
D = -16kp < 0

SO discriminant is always less than 0
</span>
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Please help asap 20 pts
eduard
The discriminant explains how many solutions the quadratic function has. It is found using this formula:

b^2-4ac

Using the formula, there are three rules. Let's say the discriminant=d:
d<0 - No solution ø
d=0 -ONLY 1 solution
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In the following graph, there are no solutions as the graph does not hit the x-axis at any point. Thereafter, the discriminant MUST be less than zero. Let's view the options check which one agrees with our answer.

A - Discriminant is greater than 0, which means two solutions. This is WRONG.
B - Discriminant is less than 0, which means no solutions. CORRECT!
C- Discriminant is equal to 0, which means one solution. WRONG!

Your answer is B.
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