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4 years ago

I'm so stuck how do you do this??

Mathematics

2 answers:

Advocard [28]4 years ago

6 0

10 1/3= 31/3
12=36/3
31/3 × 36/3=124

Len [333]4 years ago

4 0

10 1/3= 31/3
12=36/3
31/3 × 36/3=124

I hope this helped!!!:)

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T=21and u =4 what is \sqrt(t+U)

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√(t + u)

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√25

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The architects side view drawing of a saltbox-style house shows a post that supports the roof ridge. The support post is 10 ft t

pochemuha

These calculations are based on the drawing of the file enclosed.

There are three right triangles.

From the big right triangle:

a^2 + b^2 = 25^2

From the small right triangle on the left side:

(25-x)^2 + 10^2 = a^2

From the small right triangle on the right side

x^2 +10^2 = b^2

=> (25-x)^2 + 10^2 + x^2 + 10^2 = a^2 + b^2

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=> 25^2 - 50x + x^2 + 10^2 + 10^2 = 25^2

=> x^2 -50x + 100 =0

Use the quadratic formular to find the roots:

x = 2.1 and x = 47.9

Distance from back: 25 - 2.1 = 22.9 ft

Answer: 22.9 ft

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4 years ago

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Bogdan [553]

Answer:

2(3x + 7)(2x - 1)

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You can see it a little easier if you take out a common factor of 2

2(6x^2 + 11x - 7)

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Let 6 factor into 2 and 3 and the 7 into 7 and 1

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2(3x + 7)(2x - 1)

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2(6x^2 + 11x - 7)

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3 years ago

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kvv77 [185]

Answer:

1. adjacent

2. vertical

3. vertical

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Step-by-step explanation:

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3 years ago

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The arch beneath a bridge is semi-elliptical, a one-way roadway passes under the arch. The width of the roadway is 38 feet and

forsale [732]

Answer:

Only truck 1 can pass under the bridge.

Step-by-step explanation:

So, first of all, we must do a drawing of what the situation looks like (see attached picture).

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$\frac{x^2}{a^2}+\frac{y^2}{b^2}$

where:

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and we can simplify the equation, so we get:

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So, we need to know if either truk will pass under the bridge, so we will match the center of the bridge with the center of each truck and see if the height of the bridge is enough for either to pass.

in order to do this let's solve the equation for y:

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$y^{2}=144(1-\frac{x^{2}}{361})$

we can add everything inside parenthesis so we get:

$y^{2}=144(\frac{361-x^{2}}{361})$

and take the square root on both sides, so we get:

$y=\sqrt{144(\frac{361-x^{2}}{361})}$

and we can simplify this so we get:

$y=\frac{12}{19}\sqrt{361-x^{2}}$

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