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aalyn [17]
3 years ago
13

help?! so the question is: a business has $15,000 to spend on airline tickets to travel to a conference. it wants 27 of its empl

oyees to attend. the business wants to buy as many business-class seats as possible. the business-class seats cost $700. the economy-class seats cost $375. now, I need help setting up both of the equations! I had an idea of how it should go, but when I attempted to solve it, it didn't make much sense. thank you!
Mathematics
2 answers:
egoroff_w [7]3 years ago
8 0
700x + 375(27 - x) = 15000
Solve for x
X=15 business class

Economy class 27-15=12
melisa1 [442]3 years ago
7 0

Answer:

15 executive tickets

12 economic passes

Step-by-step explanation:

Resources are limited to $ 15,000. So the company must accommodate all 27 employees within that ticket budget, trying to get as many people as possible in business class.

Executive class price: $ 700

Price economy class: $ 375

Let x be the number of business class tickets:

700x + 375 (27-x) = 15,000

700x + 10,125 - 375x = 15,000

325x = 15,000 - 10,125

x = 4.875 / 325

x = 15

Therefore, the passages in economy class will be 27-15 = 12.

Then: 15 (700) + 12 (375) = 10,500 + 4500 = $ 15,000

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3 years ago
if f(1) = -5 and f(n) = f(n-1) +7, find the first four terms and the common difference of the sequence
Alex_Xolod [135]

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Step-by-step explanation:

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2 years ago
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3 years ago
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