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natta225 [31]
3 years ago
14

Parks spent 1/3 of his money on a sweater. He spent 3/5 of the remainder on a pair of jeans. If he has $36 left, how much did th

e sweater cost?
Mathematics
2 answers:
laila [671]3 years ago
8 0
1/3x + 3/5 * 2/3x = x - 36

1/3x + 6/15x = x - 36

11/15x = x - 36

4/15x = 36

x = 135

sweater costs 1/3x = 45

hope that helps, God bless!
konstantin123 [22]3 years ago
8 0
Parks had $270 in the beginning, he wasted 1/3 of it so it became $180. He spent 3/5 of the $180 which is $108. The sweater Parks bought costed $90. If you do the math the opposite, it would be 36*5=180 - 180/2=90. 90*3=270. $90 is the answer.
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Solve the problem below.
maxonik [38]

Answer:

Please post one by one answer

6 0
2 years ago
The height of a stuntperson jumping off a building that is 20 m high is modeled by the equation h = 20 -57, where t is the time
cupoosta [38]

A stuntman jumping off a 20-m-high building is modeled by the equation h = 20 – 5t2, where t is the time in seconds. A high-speed camera is ready to film him between 15 m and 10 m above the ground. For which interval of time should the camera film him?

Answer:

1\leq t\geq \sqrt{2}

Step-by-step explanation:

Given:

A stuntman jumping off a 20-m-high building is modeled by the equation

h =20-5t^{2}-----------(1)

A high-speed camera is ready to making film between 15 m and 10 m above the ground

when the stuntman is 15m above the ground.

height h = 15m  

Put height value in equation 1

15 =20-5t^{2}

5t^{2} =20-15

5t^{2} =5

t^{2} =1

t =\pm1

We know that the time is always positive, therefore t=1

when the stuntman is 10m above the ground.

height h = 10m  

Put height value in equation 1

10 =20-5t^{2}

5t^{2} =20-10

5t^{2} =10

t^{2} =\frac{10}{5}

t^{2} =2

t=\pm\sqrt{2}

t=\sqrt{2}

Therefore ,time interval of camera film him is 1\leq t\geq \sqrt{2}

7 0
3 years ago
two brothers marco and fernando are training for a marathon marco runs at a rate of 6miles per hor. Fernando funs at at a rate o
satela [25.4K]
We know that
speed=distance/time
solve for time
time=distance/speed

in this problem
<span>Marco runs at a rate of 6 miles per hour. 
</span><span>Fernando funs at a rate of 7.2 miles per hour
Difference=7.2-6=1.2 miles/hour
so
speed=1.2 miles/hour
distance=0.3 miles
time=?
</span>time=distance/speed-----> 0.3/1.2-----> 0.25 hour-----> 0.25*60=15 minutes
<span>
the answer is
0.25 hour (15 minutes)

Alternative Method
Let 
x---------> Fernando's distance when Marco is 0.3 miles apart

</span>Fernando funs at a rate of 7.2 miles per hour
<span>for distance =x
time=x/7.2------> equation 1

</span>Marco runs at a rate of 6 miles per hour. 
for distance=x-0.30
time=(x-0.30)/6------> equation 2

equate equation 1 and equation 2
 7.2*(x-0.3)=6x-----> 7.2x-2.16=6x
7.2x-6x=2.16------> x=2.16/1.2-------> x=1.8 miles

time=x/7.2-----1.8/7.2=0.25 hour
6 0
3 years ago
There are 3 boxes for green chips and 5 boxes for red chips. each box has the same number of chips in it. if there are a total o
Sauron [17]

Answer:

<h2>2 in each box of course</h2>

g= green chips       r= red chips

3 boxes of green chips meaning for each box there are <em>2</em> chips so there are 6 green chips. 5 boxes of red chips meaning for each box there are two chips so there are 10 red chips and 6 g + 10r = 16 chips in total

Step-by-step explanation:

6 0
2 years ago
Y = 16x + 8
sineoko [7]

Answer:

x + 2y = 4

  x − y = − 3

x − y =9 , x + y=6

x + y =4,

x− y =2

Step-by-step explanation:

7 0
3 years ago
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