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maks197457 [2]
3 years ago
6

Need help please anyone

Mathematics
1 answer:
kifflom [539]3 years ago
5 0
Which question do you need help with
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Suppose u=<2,−1> and v=<1,−8> are two vectors that form the sides of a parallelogram. Then the lengths of the two di
tigry1 [53]
| u | = √(2² + (-1²)) = √5
| v | = √ ( 1² + (-8)² = √65
cos (u,v) = ( u * v ) / (| u | * | v |) =
 (2 * 1 + ( -1 ) * ( - 8 )) / √5 √ 65 = (2 + 8) / √5 √65 = 10 / (√5 √ 65 )
The length of a larger diagonal:
d 1² = | u |² + 2 |u| |v| + | v |² = 5 + (2 √5 √65 * 10 / √5 √65 )+65
d 1² = 70 + 20 = 90
d 1 = √ 90 = 3√10
d 2² = 70 - 20 = 50
d 2 = √50 = 5√2
Answer:
The lengths of the diagonals are: 3√10 and 5√2 .
8 0
3 years ago
A tower stand on a horizontal plane. P is the top and Q is the bottom of the tower. A and B are two points on this plane such th
pochemuha

Answer:

32√5

Step-by-step explanation:

We have the right triangles PQA and PQB as well as the given right triangle QAB.

cot(PAQ) = 2/5 = QA/PQ

cot(PBQ) = 3/5 = QB/PQ

cot(PAQ) / cot(PBQ) = (2/5) / (3/5) = 2/3

cot(PAQ) / cot(PBQ) = (QA/PQ) / (QB/PQ) = QA / QB

QA / QB = 2/3

QA = (2/3) QB

QB = (3/2) QA

By the Pythagorean Theorem we have:

(QA)² + 32² = (QB)²

(QA)² + 32² = (3/2 QA)²

(QA)² + 1024 = (9/4) (QA)²

(5/4) (QA)² = 1024

(QA)² = (4/5)1024 = 4096/5

QA = 64/√5

Solve for PQ.

cot(PAQ) = QA/PQ

PQ = QA / cot(PAQ)

PQ = (64/√5) / (2/5) = 32√5

The height of the tower is 32√5.

7 0
4 years ago
Find the missing number in this proportion
podryga [215]

Answer:

36

Step-by-step explanation:

Cross multiply

27 x 16 all divided by 12 =36

5 0
3 years ago
If mAB = 30° and mCD = 110°, find mLE.
umka21 [38]

Answer:

40

Step-by-step explanation:

Use the Outside Angles Theorem,

\frac{110 - 30}{2}  = 40

7 0
3 years ago
A line passes through the points (1, 4) and (3,-4). Which is the equation of the line?
andrew-mc [135]

Answer:

Y=-4x+8

Step-by-step explanation:

3 0
3 years ago
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