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3 years ago

Use the Distributive Property to rewrite the algebraic expression. 5(2x + 7)

Mathematics

1 answer:

IceJOKER [234]3 years ago

6 0

Answer:

10x + 35

Step-by-step explanation:

In distributive property, you have to distribute that 5 to both the 2x and the 7, so then it would look like this:

5(2x) + 7(5)

Then we just further simplify and get:

10x + 35.

Hope this helped, let me know if you have any questions

You might be interested in

Please help I don’t understand

lesya [120]

Answer:

2·8·7
8+2+7
12·5·3
3+5+12

Step-by-step explanation:

The properties of addition and multiplication allow you to rearrange and/or regroup the components of a sum or a product. That is the point of this exercise.

(2·8)·7 = 2·(8·7) . . . . parentheses have moved: associative property

2 + 7 + 8 = 8 + 2 + 7 . . . . order is rearranged: commutative property

5·3·12 = 12·5·3 . . . . . order is rearranged: commutative property

(3 +5) +12 = 3 +(5 +12) . . . . parentheses have moved: associative property

_____

Additional comment

Whenever you're in doubt about the equivalence of numerical expressions, you can use your calculator to evaluate them. They will give the same result if they are equivalent. (You need a good scientific or graphing calculator that uses parentheses for this. Some seriously good calculators are available as low-cost phone apps.)

The Google search box also serves as input to the Google calculator. You can use an asterisk (*) for multiplication.

7 0

3 years ago

What is the factored form of x2 − 4x − 5?

laiz [17]

Factored Form:
x^2 - 4x - 5
Simplifying:
x^2 + - 4x + - 5 = 0

Reorder the terms:
- 5 + - 4x + x^2 = 0

Solving for variable " x":
Subproblem 1:
Set the factor ( - 1 + - 1x) equal to Zero and attempt to solve.

Simplifying:
- 1 + - 1x = 0

Solving:
- 1 + - 1x = 0
Move all terms containing x to the left, all other terms to the right

Add 1 to each side of equation:
- 1 + 1 + - 1x = 0 + 1

Combine Like Terms: 0 + 1 = 1
x = - 1

Divide each side by - 1
x = - 1

Simplifying: x = - 1

Subproblem 2: Set the factor (5 + - 1x) equal to Zero attempt to solve

Simplifying:
5 + - 1x = 0

Move all terms containing x to the left, all other terms to the right
Add - 5 to each side of the equation
5 + - 5 + - 1x = 0 + 5

Combine Like terms: 5 + - 5 = 0
0 + - 1x = 0 + - 5
- 1x = 0 + - 5

Combine Like Terms: 0 + - 5 = - 5
- 1x = - 5

Divide each side by - 1
x = 5

Simplifying:
x = 5

Solution:
x = { - 1, 5}

Answer when factored:
(x + 1)(x - 5)

hope that helps!!!

4 0

3 years ago

Read 2 more answers

Find the answer to 3(q+34)=2

xz_007 [3.2K]

Hey there!

3(q + 34)= 2

First distribute:

3(q) + 3(34)

3(q) = 3q

3(34) = 102

New equation: 3q + 102 = 2

Subtract by 102 on each of your sides:

3q + 102 - 102 = 2 - 102

Cancel out: 102 - 102 because it gives us 0

Keep: 2 - 102 because it helps us solve for our q

2 - 102 = - 100

New equation: 3q = -100

Divide both sides by 3

3q/3 = -100/3

Cancel out: -3q/3 because it gives us 1

Keep: -100/3 because it gives us the answer for q

Answer: q = -100/3 ✅

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)

8 0

3 years ago

PLEASE HELP ME HERE!!

Tcecarenko [31]

Answer:

Step-by-step explanation:

(1). Maryam's answer is correct.

(2). x = 2

8 0

3 years ago

A local gym instructor has a course load that allows her to teach eight classes. At an interest meeting, 8 people wanted high-‐

cricket20 [7]

Answer:

The final curse load of the local gym instructor is this:

High-‐impact aerobics = 1

Low-‐impact aerobics = 4

Jazzercise = 1

Step exercise = 2

Step-by-step explanation:

1. Let's apportion the class load using the Hamilton method

Number of classes the local gym instructor can teach = 8

Total number of students that want to take a class = 114 (8 people wanted high-‐impact aerobics, 64 wanted low-‐impact aerobics, 11 wanted jazzercise, and 31 wanted step exercise)

Standard divisor = 114/8 = 14.25

Now, we can apportion the students in in Standard quotas, this way:

High-‐impact aerobics = 8/14.25 = 0.5614

Low-‐impact aerobics = 64/14.25 = 4.49

Jazzercise = 11/14.25 = 0.7719

Step exercise = 31/14.25 = 2.1754

Now, we find the Minimum quota, just considering the whole number and don't taking into account the decimals, this way:

High-‐impact aerobics = 0

Low-‐impact aerobics = 4

Jazzercise = 0

Step exercise = 2

As we can see we have 6 classes and there are 2 still pending. Those 2 goes to the classes with the highest decimal portion, in this case, Jazzercise .7719 and High-‐impact aerobics with .5614.

The final course load is this:

High-‐impact aerobics = 1

Low-‐impact aerobics = 4

Jazzercise = 1

Step exercise = 2

7 0

3 years ago