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djverab [1.8K]
3 years ago
5

PLEASE HELP!! I do not understand this. And can you explain it for me when I use it again?

Mathematics
1 answer:
damaskus [11]3 years ago
7 0
Let's start b writing down coordinates of all points:
A(0,0,0)
B(0,5,0)
C(3,5,0)
D(3,0,0)
E(3,0,4)
F(0,0,4)
G(0,5,4)
H(3,5,4)

a.) When we reflect over xz plane x and z coordinates stay same, y coordinate  changes to same numerical value but opposite sign. Moving front-back is moving over x-axis, moving left-right is moving over y-axis, moving up-down is moving over z-axis.

A(0,0,0)
Reflecting
A(0,0,0)

B(0,5,0)
Reflecting
B(0,-5,0)

C(3,5,0)
Reflecting
C(3,-5,0)

D(3,0,0)
Reflecting
D(3,0,0)


b.)
A(0,0,0)
Moving
A(-2,-3,1)

B(0,-5,0)
Moving
B(-2,-8,1)

C(3,-5,0)
Moving
C(1,-8,1)

D(3,0,0)
Moving
D(1,-3,1)
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The Johnson family attends opening day at the tigers stadium for $165, buying two adult tickets and four child tickets. The Robi
ss7ja [257]

Answer:

The answer is that adult tickets cost $44.50 and child tickets cost $19.

Step-by-step explanation:

Let c = the cost of child tickets and a = the cost of adult tickets.

The total amount is equal to the number of adult tickets time the cost of adult tickets plus the number of child tickets times the cost of child tickets. Set up two equations:

2a + 4c = 165

4a + 3c = 235

Solve the top equation for a:

2a + 4c = 165

2a = 165 - 4c

a = 165/2 - 4c/2

a = 82.5 - 2c

Substitute into the second equation:

4a + 3c = 235

4(82.5 - 2c) + 3c = 235

330 - 8c + 3c = 235

-5c = -95

c = -95 / -5 = 19, so child ticket cost $19.

Solve for a:

a = 82.50 - 2c

a = 82.50 - 2(19)

a = 82.50 - 38

a = $44.50, so adult tickets cost $44.50.

Proof using the first equation for the Johnson family:

2a + 4c = 165

2(44.50) + 4(19) = 165

89 + 76 = 165

165 = 165

Proof using the second equation for the Robison family:

4a + 3c = 235

4(44.50) + 3(19) = 235

178 + 57 = 235

235 = 235

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4 years ago
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Step-by-step explanation:

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Answer:

x=-6, y=0

Step-by-step explanation:

it's impossible to fully solve an equation where 2 variables are unknown. So we have to make it equal to 1 set. to do this, we have to think logically.

if y=x+6, then that means wherever it says y, we can put x+6. because x+6=x+6, right? so we plug x+6 into the second equation and get.

x+6=0.5x+3

to solve for x we subtract 6 from one side and 0.5 from the other and get

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3 years ago
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