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Bas_tet [7]
3 years ago
10

Can 15/8 be simplified

Mathematics
1 answer:
Olegator [25]3 years ago
3 0

No it can't

In mixed number form it's 1 7/8

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AB and CD are straight line segments.
frutty [35]

Answer:

<h2>i) Angle AOC is 95° </h2>

Reason:- Angle AOC is equal to Angle DOB since they are Vertically Opposite Angles.

<h2>ii) Angle BOC is 85°</h2>

Reason:- Angle AOC + Angle BOC - 180° (they lie in a straight line so they are a linear pair. Sum of the angles will be 180°)

Angle AOC is 95°, So:-

95° + Angle BOC = 180°

Angle BOC= 180° - 95°

<h3><u>Angle BOC = 85°</u></h3>

<u></u>

<h2>iii) Angle DOE is 17°</h2>

Reason:- Angle AOE+ Angle DOE+ Angle DOB = 180° (they lie in a straight line so they're a linear pair. Sum of the angles will be 180°)

So,

68° + Angle DOE+ 95° = 180°

163° + Angle DOE = 180°

Angle DOE= 180° - 163°

<h3><u>Angle DOE is 17°</u></h3>
5 0
3 years ago
I need help on this
Molodets [167]

Answer:

(in order)

Size small shirts: 18, 36, 63, 1800

Size large shirts: 4, 8, 14, 200

Step-by-step explanation:

For every 9 small, there is 2 large, therefore if there is 18 small, then there is 4 large because there are two 9s in 18.

6 0
3 years ago
Find the area of the shaded regions? plss helppp
gregori [183]

Answer:

Larger shaded area = 48pi m^2 and

the small circle has area 4pi m^2.

If you require the as  decimal values they are

150.80 m^2 and 12.57 m^2 to the nearest hundredth.

Step-by-step explanation:

The area of the whole circle = pi r^2 = pi  8^2 = 64pi.

The area of the middle sized circle = pi 4*2 = 16pi.

So the area of the larger shaded region

= 64pi - 16pi = 48pi m^2.

The area of the small circle =  pi r^2 = 2^2 pi = 4pi m^2.

3 0
3 years ago
Can someone help me with this question, I got it wrong.
lukranit [14]

Answer:

8.29

Step-by-step explanation:

degrees of sector / by 360 * by pi* r^2

8 0
4 years ago
F(x) = 3x - 2x²-4<br> g(x) = x² – 3
kvasek [131]

Answer:f(2x+2)=4x2+2x−2

Step-by-step explanation:

7 0
4 years ago
Read 2 more answers
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