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3 years ago

8

X^5/x^-3 Multiply or divide.

1 answer:

Inessa05 [86]3 years ago

3 0

The answer to the question is x^8.

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What curve passes through the point (1 ,2) and has an arc length on the interval [2,6] given by Integral from 2 to 6 StartRo

Georgia [21]

Answer:

Step-by-step explanation:

Given

Length of curve

$L=\int_{2}^{6}\sqrt{1+64x^{-6}}dx$

Length of curve is given by

$L=\int_{a}^{b}\sqrt{1+\left ( \frac{\mathrm{d} y}{\mathrm{d} x}\right )^2}dx$ over interval a to b

comparing two we get

$\frac{\mathrm{d} y}{\mathrm{d} x}=8x^{-3}$

$dy=8x^{-3}dx$

integrating

$\int dy=\int 8x^{-3}dx$

$y=-4x^{-2}+C$

Curve Passes through (1,2)

$1=-4+C$

$C=5$

curve is

$y+\frac{4}{x^2}=5$

3 0

3 years ago

HELP PLEASE! <br><br><br><br><br><br>Please explain Slovin's formula

ycow [4]

Answer:

I need more information, meaning his formula.

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

The force F between 2 objects is inversely proportional to the square of the distance, d between them. The force is 0.36 newtons

LenaWriter [7]

Answer:

0.73 N to 2 dp.

Step-by-step explanation:

F = k/d^2 where k is a constant , F = force and d = distance.

Substituting:

0.36 = k / (6)^2

k = 36*0.36 = 12.96 s the equation is F = 12.96 / d^2.

When d = 4.2 :

F = 12.96 / 4.2^2

F = 0.73 Newtons to 2 dp.

5 0

3 years ago

10 is subtracted from 2 times a number

Elena-2011 [213]

Answer: the equation is 2n-10

8 0

3 years ago

For what values of $x$ is $$\frac{x^2 + x + 3}{2x^2 + x - 6} \ge 0?$$ note: be thorough and explain why all points in your answe

Rus_ich [418]

To solve the inequality $\frac{x^2+x+3}{2x^2+x-6}\ge \:0$

$\mathrm{Factor\:the\:left\:hand\:side\:}\frac{x^2+x+3}{2x^2+x-6}:$

The numerator $x^2+x+3$ is not factorizable.

so factor the denominator $2x^2+x-6$ :

$2x^2+x-6=\left(2x^2-3x\right)+\left(4x-6\right)=x\left(2x-3\right)+2\left(2x-3\right)\\ \mathrm{Factor\:out\:}x\mathrm{\:from\:}2x^2-3x\mathrm{:\quad }x\left(2x-3\right)\\ \mathrm{Factor\:out\:}2\mathrm{\:from\:}4x-6\mathrm{:\quad }2\left(2x-3\right)\\$

Now take $\mathrm{Factor\:out\:common\:term\:}\left(2x-3\right)$

Then we get factor of the denominator as $\left(2x-3\right)\left(x+2\right)$

Thus $\frac{x^2+x+3}{2x^2+x-6}=\frac{x^2+x+3}{\left(x+2\right)\left(2x-3\right)}$

Now $\mathrm{Compute\:the\:signs\:of\:the\:factors\:of\:}\frac{x^2+x+3}{\left(x+2\right)\left(2x-3\right)}\\$

Signs of $x^2+x+3>0$

$\mathrm{Choosing\:ranges\:that\:satisfy\:the\:required\:condition:}\:\ge \:\:0$

$x\frac{3}{2}$ is the required solution of the given inequality.

5 0

3 years ago

Read 2 more answers