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IgorLugansk [536]
2 years ago
10

What is the following product?

Mathematics
2 answers:
VMariaS [17]2 years ago
6 0

For this case we must find the product of the following expression:

\sqrt {12} * \sqrt {18}

We combine using the product rule for radicals:

\sqrt [n] {a} * \sqrt [n] {b} = \sqrt [n] {ab}

So, we have:

\sqrt {12 * 18} =\\\sqrt {216} =

We rewrite the 216 as6 * 6 * 6 = 6 ^ 3 = 6 ^ 2 * 6

\sqrt {6 ^ 2 * 6} =

By definition of properties of powers and roots we have:

\sqrt [n] {a ^ n} = a ^ {\frac {n} {n}} = a

Then, the expression is:

6 \sqrt {6}

Answer:

Option D

Sidana [21]2 years ago
4 0

ANSWER

6 \sqrt{6}

EXPLANATION

The given product is

\sqrt{12}  \times  \sqrt{18}

We rewrite to get;

\sqrt{4 \times 3}  \times  \sqrt{9 \times 2}

We split the radical sign to get:

\sqrt{4 }  \times   \sqrt{3} \times  \sqrt{9}  \times  \sqrt{2}

The perfect squares simplifies to:

2\sqrt{3}  \times 3 \sqrt{ 2}

This gives us :

2 \times 3 \sqrt{3 \times 2}

This simplifies to;

6 \sqrt{6}

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<img src="https://tex.z-dn.net/?f=%5Cfrac%20%7B%205%20x%20%5E%20%7B%202%20%7D%20-%2029%20x%20-%206%20%7D%20%7B%203%20x%20%5E%20%
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Answer:

Step-by-step explanation:

Vertical Asymptote: x=2Horizontal Asymptote: NoneEquation of the Slant/Oblique Asymptote: y=x 3+23 Explanation:Given:y=f(x)=x2−93x−6Step.1:To find the Vertical Asymptote:a. Factor where possibleb. Cancel common factors, if anyc. Set Denominator = 0We will start following the steps:Consider:y=f(x)=x2−93x−6We will factor where possible:y=f(x)=(x+3)(x−3)3x−6If there are any common factors in the numerator and the denominator, we can cancel them.But, we do not have any.Hence, we will move on.Next, we set the denominator to zero.(3x−6)=0Add 6 to both sides.(3x−6+6)=0+6(3x−6+6)=0+6⇒3x=6⇒x=63=2Hence, our Vertical Asymptote is at x=2Refer to the graph below:enter image source hereStep.2:To find the Horizontal Asymptote:Consider:y=f(x)=x2−93x−6Since the highest degree of the numerator is greater than the highest degree of the denominator,Horizontal Asymptote DOES NOT EXISTStep.3:To find the Slant/Oblique Asymptote:Consider:y=f(x)=x2−93x−6Since, the highest degree of the numerator is one more than the highest degree of the denominator, we do have a Slant/Oblique AsymptoteWe will now perform the Polynomial Long Division usingy=f(x)=x2−93x−6enter image source hereHence, the Result of our Long Polynomial Division isx3+23+(−53x−6)

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It was D on mine tho so check the graph

Step-by-step explanation:

I got it right on edg

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\frac{sin^2x}{cos^2x} + sin x *cscx\\ tan^2x + \frac{sin x}{sin x} \\ tan^2x + 1\\ sec^2x

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