1100/2
=550
because 100% is 500 and 100% is last year's population
To solve this problem, let us say that:
money invested in stock A = A
money invested in stock B = B
money invested in stock C = C
The given problem states that:
C = A * (1 / 4) = 0.25 A
B = A * (1 / 2) = 0.50 A
It was stated that we only have $16,000 to invest.
Therefore:
A + B + C = 16,000
Substituting values of C and B in terms of A:
A + 0.50 A + 0.25 A = 16,000
1.75 A = 16,000
A = $9,142.86
So C and B is:
C = 0.25 (9142.86)
C = $2285.71
B = 0.50 (9142.86)
B = $4571.43
Answer:
352
but for the 3 it would be 264
Answer: yes they probably are because they can be any size
Answer:
4
Step-by-step explanation:
