10 sticks bbbkbsv kbm jhd mb bd h
9=m-4
9+4=m
13=m
9=13-4
9=9
I hope this answer helped you!!! Thank you!!!
Answer:
a=216.
Step-by-step explanation:
What you do is you need to get a by itself.
a/6-11=25. You first add 11 to both sides.
a/6=36. Next you will times 6 on both sides to get
a=216 as your answer.
The length and width of rectangular traffic sign are 40 and 30 inches respectively
<h3><u>Solution:</u></h3>
Given that,
Perimeter of rectangular traffic sign = 140 inches
Let length and width be denoted as ‘L’ and ‘B’ respectively
Given that length is 10 inches longer than its width
L = 10 + B
<em><u>The perimeter of rectangle is given as:</u></em>
Perimeter = 2( L + B)
On substituting the values, we get
140 = 2(10 + B + B)
140 = 2(10 + 2B)
140 = 20 + 4B
B = 30
Therefore, the length is L = 10 + 30 = 40
Hence the dimensions length and width of the rectangle are 40 and 30 inches respectively.
Answer:Definition area"? Do you mean the "natural domain" of the function- the region in which the formula is defined? In order that a number have a square root that number must be non-zero.
Step-by-step explanation:Here, we must have x−1x≥0.
If x is positive, multiplying both sides by x we have x2−1=(x−1)(x+1)≥0. In order for that to be true, both x- 1 and x+ 1 must have the same sign: either x-1> 0 and x+ 1> 0 or x- 1< 0 and x+ 1< 0. The first pair of inequalities is true for x> 1 and the second for x< -1. Since "x is positive", we must have x> 1.
If x is negative, multiplying both sides by x we have x2−1=(x−1)(x+1)≥0. In order for that to be true, x- 1 and x+ 1 must have opposite signs: x+ 1> 0 and x- 1< 0 or x- 1<0 and x- 1> 0. The first pair is true for −1≤0≤1. The second pair are never both true. Since "x is negative" we must have −1≤x≤0.
Of course, we also cannot divide by 0 so x= 0 is not in the domain. The domain is the union of the two separate sets:{x|−1≤x<0}∪{x|x>1}.
Hope That Helps!
