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3 years ago

Kyler ran 1/5 of a mile in 1 1/2 minutes how long will it take him to run 1/2 of a mile

Mathematics

1 answer:

ivanzaharov [21]3 years ago

3 0

Answer:

1/5 mile in 11/2 minutes

1 mile in 55/2 minutes

hence, 1/2 mile in 55/4 minutes

Step-by-step explanation:

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Which graph represents x> 5?

docker41 [41]

Can you post a picture with more explanation

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3 years ago

Write a quadratic equation in the form x² + bx+c=0 that has the following

vfiekz [6]

Answer:

x^2-6x+5

Step-by-step explanation:

To have roots at x=5 and x=1 you need to write is as follows

(x-5)(x-1)

you then need to multiply these two and get

x^2-6x+5

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2 years ago

Mathew decides to run his first 50K (km) Ultra-Marathon. If 0.62 miles = 1 km, how many miles is Mathew going to run? * (please

kirza4 [7]

Answer:

31 miles

Step-by-step explanation:

If you multiply 0.62 by 50 you will get 31.

Please keep in mind that I am human and make mistakes. This answer could be wrong but this is my opinion on what the answer is.

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3 years ago

Read 2 more answers

Can someone help me please

zavuch27 [327]

Answer:

$\: \\ diameter = 4ft \\ \: raduis \: = \frac{diameter}{2} \\ raduis = \frac{4ft}{2} = 2ft \\ c = 2\pi \: r \\ c = 2\pi2ft \\ c = 4\pi \: ft \\ c = 4 \times 3.14 = 12.56ft$

8 0

2 years ago

The following integral requires a preliminary step such as long division or a change of variables before using the method of par

shtirl [24]

Division yields

$\dfrac{x^4+7}{x^3+2x} = x-\dfrac{2x^2-7}{x^3+2x}$

Now for partial fractions: you're looking for constants a, b, and c such that

$\dfrac{2x^2-7}{x(x^2+2)} = \dfrac ax + \dfrac{bx+c}{x^2+2}$

$\implies 2x^2 - 7 = a(x^2+2) + (bx+c)x = (a+b)x^2+cx + 2a$

which gives a + b = 2, c = 0, and 2a = -7, so that a = -7/2 and b = 11/2. Then

$\dfrac{2x^2-7}{x(x^2+2)} = -\dfrac7{2x} + \dfrac{11x}{2(x^2+2)}$

Now, in the integral we get

$\displaystyle\int\frac{x^4+7}{x^3+2x}\,\mathrm dx = \int\left(x+\frac7{2x} - \frac{11x}{2(x^2+2)}\right)\,\mathrm dx$

The first two terms are trivial to integrate. For the third, substitute y = x ² + 2 and dy = 2x dx to get

$\displaystyle \int x\,\mathrm dx + \frac72\int\frac{\mathrm dx}x - \frac{11}4 \int\frac{\mathrm dy}y \\\\ =\displaystyle \frac{x^2}2+\frac72\ln|x|-\frac{11}4\ln|y| + C \\\\ =\displaystyle \boxed{\frac{x^2}2 + \frac72\ln|x| - \frac{11}4 \ln(x^2+2) + C}$

7 0

2 years ago