The answer is C <<<=====
It can't be anything else. It is not a right angle. A>90
It can't be acute because one angle is greater than 90.
It can't scalene because at least 2 of the angles (and 2 sides) are equal.
The answer for the expression is C.
Maybe 2/2 I’m not sure. Sorry if it’s wrong.
Answer:

Step-by-step explanation:
Area of the Pond A= 
The increase in the area of the pond as it moves outward is: 

Since the area of the circle formed increases at the rate of 100 square feet per minute.
= 100 Square feet per minute
When the radius, r = 5 feet, we want to determine the rate at which the radius is changing,
.
