Answer:
A. 9x^4 and 3x^5y
Step-by-step explanation:
there are two ways to solve this:
first way:
You can solve this my substituting numbers for x and y in this case i used 2 for x and 3 for y and see which one is equal to the original equations
the second way is the regular way
when you add or subtract numbers with variables and exponents you want to add the constants and add the exponents in this case
is the same as
=
and you can do the same process for subtraction
= 
Answer:
16Km due east of school P
Step-by-step explanation:
Given
A school P is 16km due west of a school Q
Thus, we can say that distance PQ = 16 km.
________________________________
now we have to find the bearing of Q from P
As distance is same
distance PQ = distance QP
Thus,
Distance will remain same of 16 km.
For direction,
If Q is west of P, then P will be east of Q
as shown in figure P is west of Q,
now from point P , Q is west P.
Thus,
Bearing of School Q from P is 16Km due east of school P
Answer:
y=16
Step-by-step explanation:
Y = -10x + 1...slope here is -10. A perpendicular line will have a negative reciprocal slope. To find the negative reciprocal of a number, flip the number and change the sign. So our perpendicular line will need a slope of 1/10.
y = mx + b
slope(m) = 1/10
(5,7)....x = 5 and y = 7
now sub and find b, the y int
7 = 1/10(5) + b
7 = 1/2 + b
7 - 1/2 = b
14/2 - 1/2 = b
13/2 = b
so ur perpendicular line going thru (5,7) is y = 1/10x + 13/2
Answer:
(-2, -3)
Step-by-step explanation:
2x + 1 = 3x + 3
minus 3 from both sides
2x - 2 = 3x
minus 2x from both sides
-2 = x
then plug in -2 for x
y = 2(-2) + 1
y = -4 + 1
y = -3
(-2, -3).