Question

If side A is twice as long as B and C is 25 using the Pythagorean Theorem,What are the lengths of side A and B? Round to the nearest tenth if necessary

Answer 1

Answer:

The lengths of side A is 22.4 and B is 11.9.

Step-by-step explanation:

Given:

If side A is twice as long as B and C is 25 using the Pythagorean Theorem.

Now, to find the lengths of side A and B.

Let the side B be $x.$

So, the side A be $2x.$

Side C = 25.

Now, to solve by using Pythagorean Theorem:

A² + B² = C²

$(2x)^2+(x)^2=(25)^2$

$4x^2+x^2=625$

$5x^2=625$

Dividing both sides by 5 we get:

$x^2=125$

Using square root on both sides we get:

$x=11.18.$

B rounding to the nearest tenth =  11.9.

Now, to get A by substituting the value of $x$:

$2x\\=2\times 11.18\\=22.36.$

A rounding to the nearest tenth =  22.4.

Therefore, the lengths of side A is 22.4 and B is 11.9.