Answer:
<u>The lengths of side A is 22.4 and B is 11.9</u>.
Step-by-step explanation:
Given:
If side A is twice as long as B and C is 25 using the Pythagorean Theorem.
Now, to find the lengths of side A and B.
Let the side B be ![x.](https://tex.z-dn.net/?f=x.)
So, the side A be ![2x.](https://tex.z-dn.net/?f=2x.)
Side C = 25.
Now, to solve by using Pythagorean Theorem:
A² + B² = C²
![(2x)^2+(x)^2=(25)^2](https://tex.z-dn.net/?f=%282x%29%5E2%2B%28x%29%5E2%3D%2825%29%5E2)
![4x^2+x^2=625](https://tex.z-dn.net/?f=4x%5E2%2Bx%5E2%3D625)
![5x^2=625](https://tex.z-dn.net/?f=5x%5E2%3D625)
<em>Dividing both sides by 5 we get:</em>
![x^2=125](https://tex.z-dn.net/?f=x%5E2%3D125)
<em>Using square root on both sides we get:</em>
![x=11.18.](https://tex.z-dn.net/?f=x%3D11.18.)
<u>B rounding to the nearest tenth = 11.9.</u>
Now, to get A by substituting the value of
:
![2x\\=2\times 11.18\\=22.36.](https://tex.z-dn.net/?f=2x%5C%5C%3D2%5Ctimes%2011.18%5C%5C%3D22.36.)
<u>A rounding to the nearest tenth = 22.4.</u>
Therefore, the lengths of side A is 22.4 and B is 11.9.