Answer:
19.2 kg
Step-by-step explanation:
Amount of Bananas consumed in US per year = 5.77 million metric tons
Since 1 million = and 1 metric ton = 1000 kg, we can write:
Amount of Bananas consumed in US per year = metric tons
Amount of Bananas consumed in US per year = kg
Number of people in US = 301 million =
We have to find how many kilograms of bananas are consumed per person in 1 year in US. For this we have to divide the total amount of bananas eaten in US per year with total number of people in US, which will be:
This means, 19.2 kilograms of bananas are eaten in US per person in a year.
The answer would be
<span>59 and 60.</span>
The X and Y angles created by lines intersection in the pictures are 18° and 54°.
Based on the picture, angle ∠MON is a right angle hence it has an 90° angle. We then know that the ∠MOA is 72°. Because angle ∠MOA lies within the angle ∠MON, hence we can write the following formula:
∠MON = ∠MOA +∠AON = 90°
∠MON = 72° + ∠AON = 90°
∠AON = 18° ... (i)
If we focus on the line CD being intersected by the line AB, hence we can conclude that the angles form by this intersection will follow these rules:
∠AOD = ∠BOC
∠AOC = ∠BOD
∠AOD + AOC = 180°
∠BOC + ∠BOD = 180°
Based on the picture, we know that:
∠BOC = x
∠AOC = ∠MOA + ∠MOC
∠AOC = 72° + y ...(ii)
∠AOD = ∠AON + ∠NOD
∠AOD = 18° +2x
∠BOC = 3x ... (iii)
Because we already know that ∠BOC = AOD, hence we could rewrite the formula into:
∠BOC = ∠AOD
3x = 18° + 2x
x = 18° ... (iv)
To find the value of y, we need to focus on angle ∠AOC. Based on the previous calculations and formulas, we know that:
∠AOC + ∠BOC = 180° ... (v)
Input equations (ii) and (iv) into (v)
∠AOC + ∠BOC = 180°
(72° + y) + 3x = 180°
72° + y + 3(18°) = 180°
126° + y = 180°
y = 54° ... (vi)
Learn more about the angles by lines intersection here: brainly.com/question/2077876?referrer=searchResults
#SPJ1
Answer:
A
Step-by-step explanation:
<u>Given</u><u> </u><u>info:</u><u>-</u>If the radius of a right circular cylinder is doubled and height becomes 1/4 of the original height.
Find the ratio of the Curved Surface Areas of the new cylinder to that of the original cylinder ?
<u>Explanation</u><u>:</u><u>-</u>
Let the radius of the right circular cylinder be r units
Let the radius of the right circular cylinder be h units
Curved Surface Area of the original right circular cylinder = 2πrh sq.units ----(i)
If the radius of the right circular cylinder is doubled then the radius of the new cylinder = 2r units
The height of the new right circular cylinder
= (1/4)×h units
⇛ h/4 units
Curved Surface Area of the new cylinder
= 2π(2r)(h/4) sq.units
⇛ 4πrh/4 sq.units
⇛ πrh sq.units --------(ii)
The ratio of the Curved Surface Areas of the new cylinder to that of the original cylinder
⇛ πrh : 2πrh
⇛ πrh / 2πrh
⇛ 1/2
⇛ 1:2
Therefore the ratio = 1:2
The ratio of the Curved Surface Areas of the new cylinder to that of the original cylinder is 1:2